我需要一个脚本来像cpanel checker一样,具有超过1个网址,并且该网址存储在txt文件中。
用法:python script.py list.txt
文件list.txt中的格式:https://demo.cpanel.net:2083|democom|DemoCoA5620
这是我的代码,但是它不起作用,有人可以帮我吗?
谢谢。
import requests, sys
from multiprocessing.dummy import Pool as ThreadPool
try:
with open(sys.argv[1], 'r') as f:
list_data = [line.strip() for line in f if line.strip()]
except IOError:
pass
def cpanel(url):
try:
data = {'user':'democom', 'pass':'DemoCoA5620'}
r = requests.post(url, data=data)
if r.status_code==200:
print "login success"
else:
print "login failed"
except:
pass
def chekers(url):
try:
cpanel(url)
except:
pass
def Main():
try:
start = timer()
pp = ThreadPool(25)
pr = pp.map(chekers, list_data)
print('Time: ' + str(timer() - start) + ' seconds')
except:
pass
if __name__ == '__main__':
Main()
答案 0 :(得分:0)
我以某种方式修复了您的代码,它将返回一个包含布尔数组的实际数组,该数组指示cpanel函数的成功。
from __future__ import print_function
import requests
from multiprocessing.pool import ThreadPool
try:
list_data = ["https://demo.cpanel.net:2083|democom|DemoCoA5620",
"https://demo.cpanel.net:2083|UserDoesNotExist|WRONGPASSWORD",
]
except IOError:
pass
def cpanel(url):
try:
# try to split that url to get username / password
try:
url, username, password = url.split('|')
except Exception as e:
print("Url {} seems to have wrong format. Concrete error: {}".format(url, e))
return False
# build the correct url
url += '/login/?login_only=1'
# build post parameters
params = {'user': username,
'pass': password}
# make request
r = requests.post(url, params)
if r.status_code==200:
print("login for user {} success".format(username))
return True
else:
print("login for user {} failed due to Status Code {} and message \"{}\"".format(username, r.status_code, r.reason))
return False
except Exception as e:
print("Error occured for url {} ".format(e))
return False
def chekers(url):
return cpanel(url)
def Main():
try:
# start = timer()
pp = ThreadPool(1)
pr = pp.map(chekers, list_data)
print(pr)
# print('Time: ' + str(timer() - start) + ' seconds')
except:
pass
if __name__ == '__main__':
Main()
输出:
login for user democom success
login for user UserDoesNotExist failed due to Status Code 401 and message "Access Denied"
[True, False]
请注意,我用一些固定的url代替了文件读取操作。
自从您使用request.post
以来,我猜您实际上是想向该网址发布内容。您的代码不这样做。如果只想发送请求,请使用requests.get
方法。
有关请求数据包,请参见官方文档:https://2.python-requests.org/en/master/user/quickstart/#make-a-request
,以获取更多详细信息。
还要注意
“但它不起作用”
不是问题。