我不了解如何在我的Viewmodel中集成模型

时间:2019-09-05 13:49:13

标签: c# mvvm caliburn.micro

我正在使用Wpf,CaliburnMicro和mvvm模式构建一个小型个人项目。 该应用程序是一个触摸屏,可让用户查看室温并让他选择要在气候调节器上进行的命令(通风,冷,热,关),并显示该命令是否已从气候调节器“确认”。(反馈顺序)。来自Climatizer的数据来自串行通信。 我有一个ClimControlModel类,该类封装了RoomTemperature,Order和FeedBack Order等数据。

我已经简化了ClimControl类,因此代码在StackOverflow上不会占用太多行,而我只想在View中显示RoomTemperature。

ClimControlModel.cs:

namespace WpfMetroCaliburn.Models
{
    public enum OrderValue
    {
        OFF,
        VENT1,
        VENT2,
        VENT3,
        COLD,
        HOT,
        OFFLINE
    }
    public class ClimControlModel
    {
        public float RoomTemperature { get; set; } = 99F; // fake value for testing
        public OrderValue Order { get; set; }
        public OrderValue FeedbackOrder { get; set; }


        public ClimControlModel()
        {
           // will change val of RoomTemperature and FeedcackOrder every 5 seconds
            ChangePropretiesPeriodically();
        }

        // this will simulate updating datas from Serial
        public void ChangePropretiesPeriodically()
        {
            System.Timers.Timer aTimer = new System.Timers.Timer();
            aTimer.Elapsed += new ElapsedEventHandler(OnPropretiesChangeTimerEvent);
            aTimer.Interval = 5000;
            aTimer.Enabled = true;
        }
        // Assigning random values to RoomTemperature and Feedback Order for testing purposes
        private void OnPropretiesChangeTimerEvent(object sender, ElapsedEventArgs e)
        {
            Array values = Enum.GetValues(typeof(OrderValue));
            Random random = new Random();
            FeedbackOrder = (OrderValue)values.GetValue(random.Next(values.Length));

            Random rnd = new Random();
            RoomTemperature = rnd.Next(20, 33);
            Console.WriteLine($"FakeClimControlModel: RoomTemperature is now: {RoomTemperature}");
        }
    }
}

ShellViewModel:

namespace WpfMetroCaliburn.ViewModels
{
    public class ShellViewModel : Screen
    {

        private ClimControlModel _clim;

        public ClimControlModel Clim
        {
            get { return _clim; }
            set {
                _clim = value;
                NotifyOfPropertyChange(() => Clim);
            }
        }

        public ShellViewModel()
        {
            Clim = new ClimControlModel();
        }
    }
}

Xaml:

Window x:Class="WpfMetroCaliburn.Views.ShellView"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:WpfMetroCaliburn.Views"
        mc:Ignorable="d"
        Title="ShellView" Height="450" Width="800">
    <Grid>
        <TextBlock x:Name="Clim_RoomTemperature" FontSize="25"></TextBlock>
    </Grid>
</Window>

我知道它不起作用,因为ClimControlModel实例实际上不会触发NotifyOfPropertyChange,因为对象本身不会更改,而是对象属性的值发生更改。 但是,在那种情况下,什么是“最佳实践”,就像我在ViewModel中创建RoomTemperature,Order,Feedback Order属性一样,如何在ViewModel中自动更改其值?

1 个答案:

答案 0 :(得分:1)

随着模型属性的变化,视图注意到变化的唯一方法是模型实现INotifyPropertyChanged并在属性变化时提高NotifyPropertyChanged

换句话说,对于模型中的每个属性,更改此样式:

public float RoomTemperature { get; set; }

private float roomTemperature;
public float RoomTemperature 
{ 
    get => this.roomTemperature;
    set
    {
        this.roomTemperature=value;
        this.NotifyPropertyChanged();
    } 
}

相反,如果您在ViewModel中添加了类似的属性,则在模型更改时不会收到通知。

另一种方法是让ViewModel订阅Timer事件,然后引发NotifyPropertyChanged事件。