Scrapy搜寻器遵循包含关键字的链接

时间:2019-09-05 00:48:36

标签: python scrapy web-crawler output

我有一个运行良好的抓取工具。但是,我只希望它遵循包含特定关键字或短语的链接。我以为知道了,但是我的输出不正确。

from scrapy.selector import HtmlXPathSelector
from scrapy.linkextractors import LinkExtractor
from scrapy.spiders import CrawlSpider, Rule
from scrapy.utils.url import urljoin_rfc
from webcrawler.items import SitegraphItem


class GraphspiderSpider(CrawlSpider):
    name = "examplespider"
    custom_settings = {
    'DEPTH_LIMIT': '2',
    }
    allowed_domains = []
    start_urls = (
        'http://www.example.com/products/',
    )

    rules = (
        Rule(LinkExtractor(allow=r'/'), callback='parse_item', follow=True),
    )

    def parse_item(self, response):
        hxs = HtmlXPathSelector(response)
        i = SitegraphItem()
        i['url'] = response.url
        # i['http_status'] = response.status
        llinks=[]
        for anchor in hxs.select('//a[text()="keyword"]/@href'):
            href=anchor.select('@href').extract()[0]
            if not href.lower().startswith("javascript"):
                llinks.append(urljoin_rfc(response.url,href))
        i['linkedurls'] = llinks
        return i

    def _response_downloaded(self, response):
        filename = response.url.split("/")[-1] + '.html'
        with open(filename, 'wb') as f:
            f.write(response.body)    
        rule = self._rules[response.meta['rule']]
        return self._parse_response(response, rule.callback, rule.cb_kwargs, rule.follow)

我在hxs.select段中添加了“关键字”语句,但这显然是不正确的。我不确定如何正确使用关键字。

1 个答案:

答案 0 :(得分:0)

查看是否可以使用LinkExtractor属性来实现链接过滤逻辑。

否则,请使用Spider而不是CrawlSpiderCrawlSpider仅在其支持的有限用例中有用; Spider适用于所有用例。