Question

该命令的语法是：！giveaway（多少个获胜者）（时间）（获得）然后，您可以做出反应以获得获胜的机会，但是：问题是做出反应的用户可以赢得多次。我不知道该怎么解决

message.delete();
    var item = "";
    var time;
    var winnerCount
    let messageArray = message.content.split(" ");
    for (var i = 3; i < messageArray.length; i++) {
        item += (messageArray[i] + " ");

    }
    winnerCount = (messageArray[1]);
    if(!winnerCount) return message.channel.send("You must specify the number of winners!");
   time = (messageArray[2]);
   if(!time) return message.channel.send("You have to specify the time of the giveaway!")
    if(!item) return message.channel.send("You have to specify the prize of the giveaway!")
var embed = new Discord.RichEmbed()
.setAuthor(item)
.setDescription(`React with ? to enter! ${winnerCount} Winner(s)`)
.setFooter(`The giveaway lasts ${time} and was started at ${date.format(now, 'YYYY/MM/DD')} / ${date.format(now, 'HH:mm:ss')}!`)
var embedSent = await message.channel.send(embed);
embedSent.react("?");
setTimeout(function() {
var peopleReacted = embedSent.reactions.get("?").users.filter(user => user.id !== client.user.id).array()
if(peopleReacted.length === 0) return message.channel.send("Unfortunately, nobody took part in the giveaway! :(")
var index = Math.floor(Math.random() * peopleReacted.length)
var winners = [];
var winnerMessage = "";
for (var i = 0; i < winnerCount; i++){
    winners.push(peopleReacted[index]);

}
for (var i = 0; i < winners.length; i++) {
    winnerMessage += (winners[i].toString() + " ");

}
let haveHas = winners.length === 1 ? "has" : "have"

if(winnerCount < winners.length) return;
message.channel.send(winnerMessage + "" + haveHas + ` won **${item}**`);
let embed = new Discord.RichEmbed()
.setAuthor(`${item}`)
.setDescription(`Winner(s): ${winnerMessage}`)
.setFooter(`The giveaway ended!`)
embedSent.edit(embed)
}, ms(time))```

Answer 1

问题在以下几行之内：

var index = Math.floor(Math.random() * peopleReacted.length)
var winners = [];
var winnerMessage = "";
for (var i = 0; i < winnerCount; i++){
    winners.push(peopleReacted[index]);

}

我建议将获奖者推向一个阵营。选择新的获胜者时，检查它是否已存在于数组中，如果不存在，则按，否则画出新的获胜者。

没有javacript专家，但是类似：

var index = Math.floor(Math.random() * peopleReacted.length)
var winners = [];
var winnerMessage = "";
for (var i = 0; i < winnerCount; i++){
    if(! winners.includes(index)) winners.push(peopleReacted[index]);
    else i--; // Don't progress the loop if no winner is selected.
}

Answer 2

正如Dexirian所说的here，

问题在以下几行之内：

var index = Math.floor(Math.random() * peopleReacted.length);
var winners = [];
var winnerMessage = "";
for (var i = 0; i < winnerCount; i++){
    winners.push(peopleReacted[index]);
}

我建议将获奖者推向一个阵营。选择新的获胜者时，检查它是否已存在于数组中，如果不存在，则按，否则画出新的获胜者。

我想补充一点，提到您只选择一个索引并重新使用它，因此每次都将同一个人添加到winners中。我将执行以下操作：

var winners = [];
var winnerMessage = "";
if(peopleReacted.length < winnerCount){
   winners = peopleReacted; // Add everyone to the list of winners if the number of participants is less than or equal to the number winners
}
else{
    let index = 0;
    for(var i = 0; i < winnerCount; i++){
        index = Math.floor(Math.random() * (peopleReacted.length - 1)); // Subtract 1 from peopleReacted.length to prevent an Array Out of Bounds exception
        if(!winners.includes(peopleReacted[index])) winners.push(peopleReacted[index]);
        else i--; // Don't progress the loop if no winner is selected.
    }
}

那应该做到。让我知道您是否有任何疑问！

Answer 3

var index = Math.floor(Math.random() * peopleReacted.length)
var winners = [];
var winnerMessage = "";
for (var i = 0; i < winnerCount; i++){
    winners.push(peopleReacted[index]);
}

由于只定义一次索引，因此winners循环的每次迭代都将同一用户推入for数组。

每次确定一个新的获胜者，然后从选择池中删除所选的获胜者，以免再次被选中。

if (peopleReacted.length < winnerCount) { // Make sure there's enough users, not just 0
  return message.channel.send("Unfortunately, not enough users took part in the giveaway! :(")
    .catch(console.error);
}

const winners = [];
const winnerMessage = "";

for (let i = 0; i < winnerCount; i++) {
  const index = Math.floor(Math.random() * peopleReacted.length);
  winners.push(peopleReacted[index]); // Pick a randomly selected user as a winner
  peopleReacted.splice(index, 1); // Remove that user from the pool to be selected from
}

一名玩家可以通过赠品命令（Discord.js）赢得数次

3 个答案: