如何将OutputStream转换为InputStream?

时间:2011-04-25 13:11:58

标签: java inputstream outputstream

我正处于开发阶段,我有两个模块,其中一个我输出为OutputStream,第二个只接受InputStream。你知道如何将OutputStream转换为InputStream(反之亦然,我的意思是这样),我将能够连接这两个部分吗?

由于

12 个答案:

答案 0 :(得分:162)

似乎有许多链接和其他类似的东西,但没有使用管道的实际代码。使用java.io.PipedInputStreamjava.io.PipedOutputStream的优点是没有额外的内存消耗。 ByteArrayOutputStream.toByteArray()返回原始缓冲区的副本,这意味着无论你在内存中拥有什么,你现在都有两个副本。然后写入InputStream表示您现在有三个数据副本。

代码:

// take the copy of the stream and re-write it to an InputStream
PipedInputStream in = new PipedInputStream();
final PipedOutputStream out = new PipedOutputStream(in);
new Thread(new Runnable() {
    public void run () {
        try {
            // write the original OutputStream to the PipedOutputStream
            // note that in order for the below method to work, you need
            // to ensure that the data has finished writing to the
            // ByteArrayOutputStream
            originalByteArrayOutputStream.writeTo(out);
        }
        catch (IOException e) {
            // logging and exception handling should go here
        }
        finally {
            // close the PipedOutputStream here because we're done writing data
            // once this thread has completed its run
            if (out != null) {
                // close the PipedOutputStream cleanly
                out.close();
            }
        }   
    }
}).start();

此代码假定originalByteArrayOutputStreamByteArrayOutputStream,因为它通常是唯一可用的输出流,除非您正在写入文件。我希望这有帮助!关于这一点的好处是,因为它在一个单独的线程中,它也是并行工作的,所以无论消耗什么输入流都将流出旧的输出流。这是有益的,因为缓冲区可以保持较小,并且您可以减少延迟并减少内存使用。

答案 1 :(得分:95)

OutputStream是您将数据写入的地方。如果某个模块暴露了OutputStream,则期望在另一端读取某些内容。

另一方面,暴露InputStream的东西表明您需要收听此流,并且会有您可以阅读的数据。

因此可以将InputStreamOutputStream

连接起来

InputStream----read---> intermediateBytes[n] ----write----> OutputStream

正如有人提到的,这就是IOUtils copy()方法允许你做的事情。走另一条路是没有意义的......希望这有点道理

<强>更新

当然,我越是想到这一点,我就越能看出这实际上是如何要求的。我知道一些评论提到Piped输入/输出流,但还有另一种可能性。

如果公开的输出流是ByteArrayOutputStream,那么您始终可以通过调用toByteArray()方法获取完整内容。然后,您可以使用ByteArrayInputStream子类创建输入流包装器。这两个是伪流,它们基本上只包装一个字节数组。因此,以这种方式使用流在技术上是可行的,但对我来说它仍然很奇怪......

答案 2 :(得分:28)

由于输入和输出流只是起点和终点,因此解决方案是以字节数组临时存储数据。因此,您必须创建中间ByteArrayOutputStream,您可以从中创建byte[]作为新ByteArrayInputStream的输入。

public void doTwoThingsWithStream(InputStream inStream, OutputStream outStream){ 
  //create temporary bayte array output stream
  ByteArrayOutputStream baos = new ByteArrayOutputStream();
  doFirstThing(inStream, baos);
  //create input stream from baos
  InputStream isFromFirstData = new ByteArrayInputStream(baos.toByteArray()); 
  doSecondThing(isFromFirstData, outStream);
}

希望它有所帮助。

答案 3 :(得分:20)

你需要一个中间类,它们之间会缓冲。每次调用InputStream.read(byte[]...)时,缓冲类将使用从OutputStream.write(byte[]...)传入的下一个块填充传入的字节数组。由于块的大小可能不同,因此适配器类需要存储一定量,直到它足以填充读缓冲区和/或能够存储任何缓冲区溢出。

本文对这个问题的几种不同方法进行了很好的细分:

http://blog.ostermiller.org/convert-java-outputstream-inputstream

答案 4 :(得分:17)

ByteArrayOutputStream buffer = (ByteArrayOutputStream) aOutputStream;
byte[] bytes = buffer.toByteArray();
InputStream inputStream = new ByteArrayInputStream(bytes);

答案 5 :(得分:16)

答案 6 :(得分:9)

我在将ByteArrayOutputStream转换为ByteArrayInputStream时遇到了同样的问题,并使用ByteArrayOutputStream中的派生类解决了该问题,该类可以返回ByteArrayInputStream,即ByteArrayOutputStream使用package info.whitebyte.utils; import java.io.ByteArrayInputStream; import java.io.ByteArrayOutputStream; /** * This class extends the ByteArrayOutputStream by * providing a method that returns a new ByteArrayInputStream * which uses the internal byte array buffer. This buffer * is not copied, so no additional memory is used. After * creating the ByteArrayInputStream the instance of the * ByteArrayInOutStream can not be used anymore. * <p> * The ByteArrayInputStream can be retrieved using <code>getInputStream()</code>. * @author Nick Russler */ public class ByteArrayInOutStream extends ByteArrayOutputStream { /** * Creates a new ByteArrayInOutStream. The buffer capacity is * initially 32 bytes, though its size increases if necessary. */ public ByteArrayInOutStream() { super(); } /** * Creates a new ByteArrayInOutStream, with a buffer capacity of * the specified size, in bytes. * * @param size the initial size. * @exception IllegalArgumentException if size is negative. */ public ByteArrayInOutStream(int size) { super(size); } /** * Creates a new ByteArrayInputStream that uses the internal byte array buffer * of this ByteArrayInOutStream instance as its buffer array. The initial value * of pos is set to zero and the initial value of count is the number of bytes * that can be read from the byte array. The buffer array is not copied. This * instance of ByteArrayInOutStream can not be used anymore after calling this * method. * @return the ByteArrayInputStream instance */ public ByteArrayInputStream getInputStream() { // create new ByteArrayInputStream that respects the current count ByteArrayInputStream in = new ByteArrayInputStream(this.buf, 0, this.count); // set the buffer of the ByteArrayOutputStream // to null so it can't be altered anymore this.buf = null; return in; } } 的内部缓冲区初始化。这样就不会使用额外的内存和转换&#39;非常快:

{{1}}

我把这些东西放在github上:https://github.com/nickrussler/ByteArrayInOutStream

答案 7 :(得分:2)

图书馆io-extras可能很有用。例如,如果您想使用InputStream gzip GZIPOutputStream并希望它同步发生(使用默认缓冲区大小8192):

InputStream is = ...
InputStream gz = IOUtil.pipe(is, o -> new GZIPOutputStream(o));

请注意,该库具有100%的单元测试覆盖率(当然,这是值得的!)并且在Maven Central上。 Maven的依赖是:

<dependency>
  <groupId>com.github.davidmoten</groupId>
  <artifactId>io-extras</artifactId>
  <version>0.1</version>
</dependency>

请务必检查以后的版本。

答案 8 :(得分:0)

从我的角度来看,java.io.PipedInputStream / java.io.PipedOutputStream是考虑的最佳选择。在某些情况下,您可能希望使用ByteArrayInputStream / ByteArrayOutputStream。问题是您需要复制缓冲区以将ByteArrayOutputStream转换为ByteArrayInputStream。 ByteArrayOutpuStream / ByteArrayInputStream也限制为2GB。这是我编写的OutpuStream / InputStream实现,它绕过了ByteArrayOutputStream / ByteArrayInputStream限制(Scala代码,但对java开发人员来说很容易理解):

import java.io.{IOException, InputStream, OutputStream}

import scala.annotation.tailrec

/** Acts as a replacement for ByteArrayOutputStream
  *
  */
class HugeMemoryOutputStream(capacity: Long) extends OutputStream {
  private val PAGE_SIZE: Int = 1024000
  private val ALLOC_STEP: Int = 1024

  /** Pages array
    *
    */
  private var streamBuffers: Array[Array[Byte]] = Array.empty[Array[Byte]]

  /** Allocated pages count
    *
    */
  private var pageCount: Int = 0

  /** Allocated bytes count
    *
    */
  private var allocatedBytes: Long = 0

  /** Current position in stream
    *
    */
  private var position: Long = 0

  /** Stream length
    *
    */
  private var length: Long = 0

  allocSpaceIfNeeded(capacity)

  /** Gets page count based on given length
    *
    * @param length   Buffer length
    * @return         Page count to hold the specified amount of data
    */
  private def getPageCount(length: Long) = {
    var pageCount = (length / PAGE_SIZE).toInt + 1

    if ((length % PAGE_SIZE) == 0) {
      pageCount -= 1
    }

    pageCount
  }

  /** Extends pages array
    *
    */
  private def extendPages(): Unit = {
    if (streamBuffers.isEmpty) {
      streamBuffers = new Array[Array[Byte]](ALLOC_STEP)
    }
    else {
      val newStreamBuffers = new Array[Array[Byte]](streamBuffers.length + ALLOC_STEP)
      Array.copy(streamBuffers, 0, newStreamBuffers, 0, streamBuffers.length)
      streamBuffers = newStreamBuffers
    }

    pageCount = streamBuffers.length
  }

  /** Ensures buffers are bug enough to hold specified amount of data
    *
    * @param value  Amount of data
    */
  private def allocSpaceIfNeeded(value: Long): Unit = {
    @tailrec
    def allocSpaceIfNeededIter(value: Long): Unit = {
      val currentPageCount = getPageCount(allocatedBytes)
      val neededPageCount = getPageCount(value)

      if (currentPageCount < neededPageCount) {
        if (currentPageCount == pageCount) extendPages()

        streamBuffers(currentPageCount) = new Array[Byte](PAGE_SIZE)
        allocatedBytes = (currentPageCount + 1).toLong * PAGE_SIZE

        allocSpaceIfNeededIter(value)
      }
    }

    if (value < 0) throw new Error("AllocSpaceIfNeeded < 0")
    if (value > 0) {
      allocSpaceIfNeededIter(value)

      length = Math.max(value, length)
      if (position > length) position = length
    }
  }

  /**
    * Writes the specified byte to this output stream. The general
    * contract for <code>write</code> is that one byte is written
    * to the output stream. The byte to be written is the eight
    * low-order bits of the argument <code>b</code>. The 24
    * high-order bits of <code>b</code> are ignored.
    * <p>
    * Subclasses of <code>OutputStream</code> must provide an
    * implementation for this method.
    *
    * @param      b the <code>byte</code>.
    */
  @throws[IOException]
  override def write(b: Int): Unit = {
    val buffer: Array[Byte] = new Array[Byte](1)

    buffer(0) = b.toByte

    write(buffer)
  }

  /**
    * Writes <code>len</code> bytes from the specified byte array
    * starting at offset <code>off</code> to this output stream.
    * The general contract for <code>write(b, off, len)</code> is that
    * some of the bytes in the array <code>b</code> are written to the
    * output stream in order; element <code>b[off]</code> is the first
    * byte written and <code>b[off+len-1]</code> is the last byte written
    * by this operation.
    * <p>
    * The <code>write</code> method of <code>OutputStream</code> calls
    * the write method of one argument on each of the bytes to be
    * written out. Subclasses are encouraged to override this method and
    * provide a more efficient implementation.
    * <p>
    * If <code>b</code> is <code>null</code>, a
    * <code>NullPointerException</code> is thrown.
    * <p>
    * If <code>off</code> is negative, or <code>len</code> is negative, or
    * <code>off+len</code> is greater than the length of the array
    * <code>b</code>, then an <tt>IndexOutOfBoundsException</tt> is thrown.
    *
    * @param      b   the data.
    * @param      off the start offset in the data.
    * @param      len the number of bytes to write.
    */
  @throws[IOException]
  override def write(b: Array[Byte], off: Int, len: Int): Unit = {
    @tailrec
    def writeIter(b: Array[Byte], off: Int, len: Int): Unit = {
      val currentPage: Int = (position / PAGE_SIZE).toInt
      val currentOffset: Int = (position % PAGE_SIZE).toInt

      if (len != 0) {
        val currentLength: Int = Math.min(PAGE_SIZE - currentOffset, len)
        Array.copy(b, off, streamBuffers(currentPage), currentOffset, currentLength)

        position += currentLength

        writeIter(b, off + currentLength, len - currentLength)
      }
    }

    allocSpaceIfNeeded(position + len)
    writeIter(b, off, len)
  }

  /** Gets an InputStream that points to HugeMemoryOutputStream buffer
    *
    * @return InputStream
    */
  def asInputStream(): InputStream = {
    new HugeMemoryInputStream(streamBuffers, length)
  }

  private class HugeMemoryInputStream(streamBuffers: Array[Array[Byte]], val length: Long) extends InputStream {
    /** Current position in stream
      *
      */
    private var position: Long = 0

    /**
      * Reads the next byte of data from the input stream. The value byte is
      * returned as an <code>int</code> in the range <code>0</code> to
      * <code>255</code>. If no byte is available because the end of the stream
      * has been reached, the value <code>-1</code> is returned. This method
      * blocks until input data is available, the end of the stream is detected,
      * or an exception is thrown.
      *
      * <p> A subclass must provide an implementation of this method.
      *
      * @return the next byte of data, or <code>-1</code> if the end of the
      *         stream is reached.
      */
    @throws[IOException]
    def read: Int = {
      val buffer: Array[Byte] = new Array[Byte](1)

      if (read(buffer) == 0) throw new Error("End of stream")
      else buffer(0)
    }

    /**
      * Reads up to <code>len</code> bytes of data from the input stream into
      * an array of bytes.  An attempt is made to read as many as
      * <code>len</code> bytes, but a smaller number may be read.
      * The number of bytes actually read is returned as an integer.
      *
      * <p> This method blocks until input data is available, end of file is
      * detected, or an exception is thrown.
      *
      * <p> If <code>len</code> is zero, then no bytes are read and
      * <code>0</code> is returned; otherwise, there is an attempt to read at
      * least one byte. If no byte is available because the stream is at end of
      * file, the value <code>-1</code> is returned; otherwise, at least one
      * byte is read and stored into <code>b</code>.
      *
      * <p> The first byte read is stored into element <code>b[off]</code>, the
      * next one into <code>b[off+1]</code>, and so on. The number of bytes read
      * is, at most, equal to <code>len</code>. Let <i>k</i> be the number of
      * bytes actually read; these bytes will be stored in elements
      * <code>b[off]</code> through <code>b[off+</code><i>k</i><code>-1]</code>,
      * leaving elements <code>b[off+</code><i>k</i><code>]</code> through
      * <code>b[off+len-1]</code> unaffected.
      *
      * <p> In every case, elements <code>b[0]</code> through
      * <code>b[off]</code> and elements <code>b[off+len]</code> through
      * <code>b[b.length-1]</code> are unaffected.
      *
      * <p> The <code>read(b,</code> <code>off,</code> <code>len)</code> method
      * for class <code>InputStream</code> simply calls the method
      * <code>read()</code> repeatedly. If the first such call results in an
      * <code>IOException</code>, that exception is returned from the call to
      * the <code>read(b,</code> <code>off,</code> <code>len)</code> method.  If
      * any subsequent call to <code>read()</code> results in a
      * <code>IOException</code>, the exception is caught and treated as if it
      * were end of file; the bytes read up to that point are stored into
      * <code>b</code> and the number of bytes read before the exception
      * occurred is returned. The default implementation of this method blocks
      * until the requested amount of input data <code>len</code> has been read,
      * end of file is detected, or an exception is thrown. Subclasses are encouraged
      * to provide a more efficient implementation of this method.
      *
      * @param      b   the buffer into which the data is read.
      * @param      off the start offset in array <code>b</code>
      *                 at which the data is written.
      * @param      len the maximum number of bytes to read.
      * @return the total number of bytes read into the buffer, or
      *         <code>-1</code> if there is no more data because the end of
      *         the stream has been reached.
      * @see java.io.InputStream#read()
      */
    @throws[IOException]
    override def read(b: Array[Byte], off: Int, len: Int): Int = {
      @tailrec
      def readIter(acc: Int, b: Array[Byte], off: Int, len: Int): Int = {
        val currentPage: Int = (position / PAGE_SIZE).toInt
        val currentOffset: Int = (position % PAGE_SIZE).toInt

        val count: Int = Math.min(len, length - position).toInt

        if (count == 0 || position >= length) acc
        else {
          val currentLength = Math.min(PAGE_SIZE - currentOffset, count)
          Array.copy(streamBuffers(currentPage), currentOffset, b, off, currentLength)

          position += currentLength

          readIter(acc + currentLength, b, off + currentLength, len - currentLength)
        }
      }

      readIter(0, b, off, len)
    }

    /**
      * Skips over and discards <code>n</code> bytes of data from this input
      * stream. The <code>skip</code> method may, for a variety of reasons, end
      * up skipping over some smaller number of bytes, possibly <code>0</code>.
      * This may result from any of a number of conditions; reaching end of file
      * before <code>n</code> bytes have been skipped is only one possibility.
      * The actual number of bytes skipped is returned. If <code>n</code> is
      * negative, the <code>skip</code> method for class <code>InputStream</code> always
      * returns 0, and no bytes are skipped. Subclasses may handle the negative
      * value differently.
      *
      * The <code>skip</code> method of this class creates a
      * byte array and then repeatedly reads into it until <code>n</code> bytes
      * have been read or the end of the stream has been reached. Subclasses are
      * encouraged to provide a more efficient implementation of this method.
      * For instance, the implementation may depend on the ability to seek.
      *
      * @param      n the number of bytes to be skipped.
      * @return the actual number of bytes skipped.
      */
    @throws[IOException]
    override def skip(n: Long): Long = {
      if (n < 0) 0
      else {
        position = Math.min(position + n, length)
        length - position
      }
    }
  }
}

易于使用,没有缓冲区重复,没有2GB内存限制

val out: HugeMemoryOutputStream = new HugeMemoryOutputStream(initialCapacity /*may be 0*/)

out.write(...)
...

val in1: InputStream = out.asInputStream()

in1.read(...)
...

val in2: InputStream = out.asInputStream()

in2.read(...)
...

答案 9 :(得分:-1)

如果要从InputStream创建OutputStream,则存在一个基本问题。写入OutputStream的方法将一直阻塞,直到完成为止。因此,当写入方法完成时,结果可用。这有两个后果:

  1. 如果只使用一个线程,则需要等到所有内容都写完(因此需要将流的数据存储在内存或磁盘中)。
  2. 如果要在数据完成之前访问数据,则需要第二个线程。
  3. 变体1可以使用字节数组或字段来实现。 变体1可以使用pipies实现(直接或使用额外的抽象 - 例如RingBuffer或来自其他评论的google lib)。

    确实使用标准java,没有其他方法可以解决问题。每个解决方案都是其中一个解决方案的实现。

    有一个概念称为“延续”(详见wikipedia)。在这种情况下,基本上这意味着:

    • 有一个需要一定数量数据的特殊输出流
    • 如果达到ammount,则流控制它的对应方是一个特殊的输入流
    • 输入流使数据量可用,直到读取为止,然后将控制权传递回输出流

    虽然有些语言内置了这个概念,但对于java来说,你需要一些“魔力”。例如,来自apache的“commons-javaflow”为java实现了这样的功能。缺点是这需要在构建时进行一些特殊的字节码修改。因此,将所有内容放在一个额外的库中并使用自定义构建脚本是有意义的。

答案 10 :(得分:-1)

旧帖但可能会帮助其他人,使用这种方式:

OutputStream out = new ByteArrayOutputStream();
...
out.write();
...
ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(out.toString().getBytes()));

答案 11 :(得分:-1)

虽然您无法将OutputStream转换为InputStream,但java提供了一种使用PipedOutputStream和PipedInputStream的方法,您可以将写入PipedOutputStream的数据通过关联的PipedInputStream变为可用。回到某些时候我遇到了类似的情况,处理需要将InputStream实例传递给它们而不是OutputStream实例的第三方库。
我解决这个问题的方法是使用PipedInputStream和PipedOutputStream 。
顺便说一句,它们使用起来很棘手,你必须使用多线程来实现你想要的。我最近在github上发布了一个你可以使用的实现。
这是link。您可以浏览wiki以了解如何使用它。