Question

urls.py

from django.conf.urls import patterns, include, url from django.conf.urls.i18n import i18n_patterns from django.utils.translation import ugettext_lazy as _ from django.contrib import admin admin.autodiscover()

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
    url(r'^i18n/', include('django.conf.urls.i18n')), )

urlpatterns += i18n_patterns('',
    (_(r'^dual-lang/'), include('duallang.urls')),
    (r'^', include('home.urls')), )

from django.conf import settings

if 'rosetta' in settings.INSTALLED_APPS:
    urlpatterns += patterns('',
        url(r'^rosetta/', include('rosetta.urls')),
    )

获取ImportError：无法从中导入名称“模式” 'django.conf.urls'

Answer 1

您必须将模式转换为列表，可以将url伪装成路径或re_path，如下所示：

from django.urls import path, include

urlpatterns = [
    path('admin/', include(admin.site.urls)),
    path('i18n/', include('django.conf.urls.i18n'))
]

i18n_pattern可以这样使用：

from django.conf.urls.i18n import i18n_patterns
from django.urls import path, include

urlpatterns += i18n_patterns(
   path('', include('home.urls'))
)

如何修改url.py以在最新的Django版本中运行？

1 个答案: