Question

我正在构建一个电子商务应用程序，我试图将用户按下的每个项目添加到购物车中（调用functionsCombined（））保存在Firebase中，但我不想在记录中重复

this.state = {
    added: false,
    duplicate: false,
}

componentWillMount() {
    //gets the data in firebase
    this.props.fetchData();
}

functionsCombined(recipe) {
    //the user pressed add to cart
    //recipe is the item to be added
    if (this.state.added) {

    } else {
        this.functionZero(recipe);
        this.functionOne();
        this.functionTwo(recipe);
    }
}

functionZero(recipe) {
    //this.props.check is the data we pulled from firebase
    //to check if the firebase records is the same as the one here
    /but even when that's true, setState doesn't work for some reason
    this.props.check.map((one) => {
        if (one.id === recipe.id) {
            this.setState({
                duplicate: true
            })
        } else {

        }
    })
}


functionOne() {
    this.setState({
        added: true
    })
}

functionTwo(recipe) {
    if (this.state.duplicate === false) {
        const {
            currentUser
        } = firebase.auth();
        firebase.database().ref(`/users/${currentUser.uid}/recipes`)
            .push(recipe);
    } else {

    }
}

Answer 1

在保存到Firebase之前，可以使用通用唯一标识符（UUID）。像这样

const uuidv4 = require（'uuid / v4'）;

..... 
firebase.database().ref(`/users/${currentUser.uid}/recipes`+uuidv4())
            .push(recipe);

.....

这将为您保存的每个Firebase记录生成唯一的ID

如何防止Firebase记录重复

1 个答案: