Question

我从互联网上复制了一个代码，它在一个json集合中进行搜索-查找相关的键并根据合计或单个数组的操作返回其值。问题是它仅搜索其找到的值并将其汇总。我想要一个附加功能来查找哪个键具有空值。请有人来看看。

function perform(keys, operation) {
  function visit(object) {
    Object.entries(object).forEach(([k, v]) => {
      if (k in indices) return fn(result, indices[k], v);
      if (v && typeof v === "object") visit(v);
    });
  }

  var result = [],
    indices = Object.assign({}, ...keys.map((k, i) => ({ [k]: i }))),
    fn = {
      notsum: function(target, key, value) {
        if (target[key] === undefined) {
          target[key] = value;
          return;
        }
        if (!Array.isArray(target[key])) {
          target[key] = [target[key]];
        }
        target[key].push(value);
      },
      sum: function(target, key, value) {
        target[key] = (target[key] || 0) + value;
      }
    }[operation === "total" ? "sum" : operation];

  visit(data);

  //to add functionality here to get the keys with values, even if they are null

  //end
  return operation === "total" ? result.reduce((a, b) => a + b) : result;
}

工作原理

console.log(perform(["WA1", "WA3", "RAE1"], "notsum")); // [3, 2, 1]
console.log(perform(["WA1", "WA3", "RAE1"], "total"));  // 6

JSON对象可以简单也可以复杂

var data = {
  version: "1.0",
  submission: "editing",
  WebData: {
    WA1: 3,
    WA3: 2,
    WAX: "NEO",
    WebGroup: [{ Web1: 3, Web2: 0 }, { Web1: 4, Web2: 1 }]
  },
  NonWebData: { NWA1: 3, NWA2: "INP", NWA3: 2 },
  FormInputs: { FM11: 3, FM12: 1, FM13: 2 },
  RawData: {
    RawOverview: { RAE1: 1, RAE2: 1 },
    RawGroups: [
      {
        name: "A1",
        id: "1",
        data: {
          AD1: "period",
          AD2: 2,
          AD3: 2,
          transfers: [
            { type: "in", TT1: 1, TT2: 2 },
            { type: "out", TT1: 1, TT2: 2 }
          ]
        }
      },
      {
        name: "A2",
        id: "2",
        data: {
          AD1: "period",
          AD2: 2,
          AD3: 2,
          transfers: [
            { type: "in", TT1: 1, TT2: 2 },
            { type: "out", TT1: 1, TT2: 2 }
          ]
        }
      }
    ]
  },
  Other: { O1: 1, O2: 2, O3: "hello" },
  AddedBy: "name",
  AddedDate: "11/02/2019"
};

该功能的确返回索引，其中包含所有键，但是我想要键值对，因此我知道数组中哪一个根本不存在。函数中编写的代码可以给我

["WA1", "WA3", "RAE1"]
[2, null, null]

现在，它只会查找值是否存在，并将它们加起来并给我2作为结果。

非常感谢

Answer 1

您可以编写一个函数来递归访问对象树中的所有节点并执行所需的操作。以下是sum和'getBykey`的示例功能。

function perform(obj, keys = [], operation = "getByKey") {
  const results = [];
  let sum = 0;

  // Define a fucntion that traverses all nodes in your object tree
  const visit = (obj, keys = [], operation = "getByKey") => {
    if (obj && typeof obj === "object") {
      Object.entries(obj).forEach(([key, value]) => {
        if (keys.includes(key)) {
          // You can add more if_block/switch_case for more operations
          if (operation === "sum" && !isNaN(value)) {
            sum += value;
          } else {
            results.push({ [key]: value });
          }
        }
        visit(value, keys, operation);
      });
    }
  }

  // Traverse the object tree
  visit(obj, keys, operation);

  return operation === "sum" ? sum : results;
}

const getByKey = perform(data, ["WA1", "WA3", "RAE1", "AD1"]);
const sum = perform(data, ["WA1", "WA3", "RAE1"], 'sum');

console.log(sum);
console.log(getByKey);

遍历大对象并返回空值

1 个答案: