这是我第一次使用perl(v5.28.1)。我收到错误消息:
'Can't locate object method "load" via stepReader (perhaps you forgot to load 'stepReader')'.
当我在文件中打印某些内容时,它可以工作,但是以某种方式找不到我的方法。
我在名为stepReader.pm
的子目录中有src
**
example.pm
use lib 'src/';
use stepReader;
@ISA = ('stepReader');
my $class = stepReader->load('assets/glasses.STEP');
stepReader.pm
package src::stepReader;
use strict;
use warnings;
sub load {
# Variable for file path
my $filename = @_;
# Open my file
open(my $fh, '<:encoding(UTF-8)', $filename)
or die "Could not open file '$filename' $!";
# Print the file!
while (my $row = <$fh>) {
chomp $row;
print "$row\n";
}
return bless {}, shift;
}
print "test if this works!";
1;
输出:
Can't locate object method "load" via package "stepReader" (perhaps you forgot to load "stepReader"?) at example.pm line 6.
test if this works!
我怀疑这很容易,但是我希望有人可以帮助我。预先感谢
答案 0 :(得分:7)
直接的问题是您的代码中没有名为stepReader
的类,只有src::stepReader
:
package src::stepReader;
也就是说,该函数称为src::stepReader::load
,而不是stepReader::load
。将软件包声明更改为:
package stepReader;
此外,以小写字母开头的模块名称被非正式地保留给实用程序。对于普通模块,惯例是使用大写字母:
package StepReader;
(并将文件StepReader.pm
重命名以匹配)。
参数解包也坏了:
# Variable for file path my $filename = @_;
这会将@_
数组置于标量上下文中,从而提供元素数。您需要改为分配列表(在左侧带有括号),并且方法调用将调用方作为隐式的第一个参数传递:
my ($class, $filename) = @_;
...
return bless {}, $class;
或者:
my $class = shift;
my ($filename) = @_;
或
my $class = shift;
my $filename = shift;
您应始终使用use strict; use warnings;
或等效名称来启动文件。 example.pm
当前缺少它:
use strict;
use warnings;
use lib 'src';
use StepReader;
# This line is not needed, but if it were:
# our @ISA = ('StepReader');