Question

我想对文件进行排序，然后这部分工作了。排序后，我想从文件中删除每个空格行，并将其输出到另一个文件。

我只是想不通，我真的想要帮助。

bad_words = ["bad", "word"]


with open('naughtfile.txt') as oldfile, open('cleanfile', 'w') as newfile:
    for line in oldfile:
        if not any(bad_word in line for bad_word in bad_words):
            newfile.write(line)

我想对文件进行排序，删除空白行并将其保存在另一个文件中。

Answer 1

首先，您将要读取文件的内容并将行拆分为一个列表。然后，您需要对该列表进行排序，然后将符合条件的列表项写入另一个文件。我不确定空白行是什么意思，但我认为这些只是空白行。

bad_words = ["bad", "word"]

with open('naughtfile.txt') as oldfile, open('cleanfile.txt', 'w') as newfile:
    content = oldfile.read().splitlines()
    content.sort()
    for line in content:
        if not any(bad_word in line for bad_word in bad_words) and not (line is "" or line.isspace()):
            newfile.write(line + '\n')

Answer 2

from string import whitespace
from itertools import chain


bad_words = ['bad', 'words']

with open(filepath_1, 'r') as old_file, open(filepath_2, 'w') as new_file:
    lines = old_file.readlines()
    lines.sort()

    for line in lines:
        # chain together the whitespace list and bad_words list.
        if not any(strng in line for strng in chain(whitespace, bad_words)):
            # do stuff

Answer 3

您还没有显示排序，所以我不确定您想在那里做什么。至于其余的-我会使用正则表达式：

    import re
    # make regex that matches the bad words, plus empty lines
    bad_word = re.compile(r'bad|word|^\s*\n')
    # loop over the file and write the lines that don't match bad_word
    with open('naughtfile.txt') as oldfile, open('cleanfile.txt', 'w') as newfile:
        for line in oldfile:
            if bad_word.search(line):
                continue
            newfile.write(re.sub(r'\n', '', line))

从文件中删除空格并将其输出到另一个文件

3 个答案: