如何创建从列表中选择的5个随机数组成的5个列表？

Question

我想从一个数字列表中随机创建5个由5个数字组成的列表。

import random

def team():
    x = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] 
    y = []
    Count = 0
    count = 0
    while Count < 5:
        while count<5:
            count += 1
            z = random.choice(x)
            y += z
            x.remove(z)
        print(y)
        Count +=1

team()

输出：

预期输出：

我想要5组不重复的数字

Answer 1

将代码更改为

import { Injectable } from '@angular/core';
import { HttpClient } from '@angular/common/http';

import { catchError } from 'rxjs/operators';

import { Observable } from 'rxjs';
import { AppError } from '../common/validators/app-error';
import { NotFoundError } from '../common/not-found-error';
import { BadRequest } from './../common/bad-request-error';

export class DataService {
  constructor(private url: string, private httpClient: HttpClient) {
  }

  getAll(){
    return this.httpClient.get(this.url).pipe(catchError(this.handleError));
  }

  getOne(ressource){
    return this.httpClient.get(this.url + '/' + ressource).pipe(catchError(this.handleError));
  }

  create(ressource){
    return this.httpClient.post(this.url, JSON.stringify(ressource)).pipe(catchError(this.handleError));
  }

  update(ressource,oldRessource){
    return this.httpClient.put(this.url + '/' + oldRessource, JSON.stringify(ressource)).pipe(catchError(this.handleError));
  }

  delete(ressource){
    return this.httpClient.delete(this.url + '/' + ressource).pipe(catchError(this.handleError));
  }

  public handleError(err: Response){
    if (err.status == 400 ){
      return Observable.throw(new BadRequest(err));
    }

    if (err.status == 404) {
      return Observable.throw(new NotFoundError());
    }
    // Return error by default if no specific error
    return Observable.throw(new AppError(err));
  }
}

实际上，对于您的原始代码，import random def team(): Count = 0 while Count < 5: x = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] y = [] count = 0 while count<5: count += 1 z = random.choice(x) y += z x.remove(z) print(y) Count +=1 team() 变为count并中断了第二个for循环。但是下一次，您的5仍然是count，因此它不会进入第二个for循环。

您刚5第一次获得print五次五次：：）

Answer 2

如果您使用嵌套列表推导，这是一个单行代码。同样，我们可以直接对整数0..9进行采样，而不是对字符串['0', '1',...,'9']

进行列表采样

import random

teams = [[random.randrange(10) for element in range(5)] for count in range(5)]

# Here's one example run: [[0, 8, 5, 6, 2], [6, 7, 8, 6, 6], [8, 8, 6, 2, 2], [0, 1, 3, 5, 8], [7, 9, 4, 9, 6]]

或者如果您真的要输出字符串而不是整数：

teams = [[str(random.randrange(10)) for element in range(5)] for count in range(5)]

[['3', '8', '2', '5', '3'], ['7', '1', '9', '7', '9'], ['4', '8', '0', '4', '1'], ['7', '6', '5', '8', '2'], ['6', '9', '2', '7', '3']]

或者如果您真的想要随机采样任意字符串列表：

[ random.sample(['0','1','2','3','4','5','6','7','8','9'], 5) for count in range(5) ]

[['7', '1', '5', '3', '0'], ['7', '1', '6', '2', '8'], ['3', '0', '9', '7', '2'], ['5', '1', '7', '3', '2'], ['6', '2', '5', '0', '3']]