Question

以下是可重复使用的数据：

  structure(list(countyfp10 = c(1, 1, 1, 1, 3, 3, 3, 3, 5, 5, 5, 
5, 7, 7, 7, 7), id = c(7417, 7418, 7419, 7420, 7421, 7422, 7423, 
7424, 7425, 7426, 7427, 7428, 7429, 7430, 7431, 7432), lat = c(39.4797245, 
39.5544678, 39.4681687, 39.199806, 39.4017623, 39.3093943, 39.4272021, 
39.5618129, 39.7934997, 39.4835134, 39.4989196, 39.4819145, 39.4727694, 
39.4675515, 39.4693146, 39.4644503), long = c(-118.7908571, -118.8095638, 
-118.8195712, -118.5429041, -118.754186, -118.8861865, -118.9729817, 
-117.9418517, -118.9516281, -118.8487913, -119.0205114, -118.7695846, 
-118.7938896, -118.76011, -118.7778707, -118.7902103)), class = c("spec_tbl_df", 
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -16L), spec = structure(list(
    cols = list(countyfp10 = structure(list(), class = c("collector_double", 
    "collector")), id = structure(list(), class = c("collector_double", 
    "collector")), lat = structure(list(), class = c("collector_double", 
    "collector")), long = structure(list(), class = c("collector_double", 
    "collector"))), default = structure(list(), class = c("collector_guess", 
    "collector")), skip = 1), class = "col_spec"))

当前存储为data.frame，但我想将其转换为SpatialPolygonsDataFrame。最好的方法是什么？

Answer 1

为此我一直在开发sfheaders库。它尚未在CRAN上，但已经接近（如果您对使用库的开发版本感到满意）

devtools::install_github("dcooley/sfheaders")
library(sfheaders)

sf <- sfheaders::sf_polygon(
    obj = df
    , x = "long"
    , y = "lat"
    , polygon_id = "countyfp10"
)

并显示它可以在传单中使用（其他plotting libraries也可用；））

library(leaflet)
leaflet() %>%
    addTiles() %>%
    addPolygons(data = sf)

Answer 2

如评论中所述，sf是最方便使用的软件包，这是一个示例。

请注意，数据集已修改为形成封闭的多边形，如果我们将其与原始数据一起尝试，则会引发错误。

data = tibble(countyfp10 = c(1, 1, 1, 1,1, 3, 3, 3, 3,3, 5, 5, 5,5,
                              5, 7, 7, 7, 7,7), id = c(7413,7414,7415,7416,7417, 7418, 7419, 7420, 7421, 7422, 7423, 
                                                     7424, 7425, 7426, 7427, 7428, 7429, 7430, 7431, 7432), lat = c(39.4797245, 
                                                                                                                    39.5544678, 39.4681687, 39.199806,39.4797245, 39.4017623, 39.3093943, 39.4272021, 
                                                                                                                    39.5618129,39.4017623, 39.7934997, 39.4835134, 39.4989196, 39.4819145,39.7934997, 39.4727694, 
                                                                                                                    39.4675515, 39.4693146, 39.4644503,39.4727694), lng = c(-118.7908571, -118.8095638, 
                                                                                                                                                                  -118.8195712, -118.5429041,-118.7908571, -118.754186, -118.8861865, -118.9729817, 
                                                                                                                                                                  -117.9418517,-118.754186, -118.9516281, -118.8487913, -119.0205114, -118.7695846,-118.9516281, 
                                                                                                                                                                  -118.7938896, -118.76011, -118.7778707, -118.7902103,-118.7938896))

cords = data%>%
  select(countyfp10,lng,lat)%>%
  mutate(lng = as.numeric(lng),
         lat = as.numeric(lat))%>%
  group_by(countyfp10)%>%
  summarise(coordinates = list(list(matrix(c(lng,lat),ncol = 2)))) %>%
  .$coordinates %>%
  lapply(.,st_polygon) %>%
  st_sfc(.)

cords %>% 
  leaflet() %>%
  addTiles()%>%
  addPolygons()

将data.frame转换为SpatialPolygonsDataFrame

2 个答案: