Question

我的登录屏幕第一次出现抖动，我尝试了多种解析json的方法，但到目前为止都没有成功。谁能帮我得到json的回复，以便我也能对此有所了解。

---my model class

class User{
  String email;
  String password;
  String token;

  User({
    this.email,
    this.password,
    this.token
  });

  factory User.fromJson(Map<String, dynamic> parsedJson){
   // Map json = parsedJson['user'];
    return User(
        email: parsedJson['email'],
       password: parsedJson['password'],
       token: parsedJson['token']
      );
  }
}


-------
json for response.

Future loadUser() async{
   final response = await  http.get(url, headers : { 
    HttpHeaders.contentTypeHeader: 'application/json'
  }
  body : User.fromJson(response);
  print(user.token);
   );


    enter code here

}
-----

{
    "email": "zxc@example.com",
    "password": "aa718893bfe3e587047c81af40269d14",
    "token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpZCI6Mn0.MGBf"
}

Answer 1

您可以使用

解析JSON字符串

final user = userFromJson(jsonString);

或使用userToJson函数将用户对象转换为json字符串

用户分类代码

// To parse this JSON data, do
//
//     final user = userFromJson(jsonString);

import 'dart:convert';

User userFromJson(String str) => User.fromJson(json.decode(str));

String userToJson(User data) => json.encode(data.toJson());

class User {
    String email;
    String password;
    String token;

    User({
        this.email,
        this.password,
        this.token,
    });

    factory User.fromJson(Map<String, dynamic> json) => new User(
        email: json["email"],
        password: json["password"],
        token: json["token"],
    );

    Map<String, dynamic> toJson() => {
        "email": email,
        "password": password,
        "token": token,
    };
}

Answer 2

使用Flutter的官方http软件包执行GET和POST操作。

https://pub.dev/packages/http

要安装http软件包，请将其添加到pubspec.yaml的依赖项部分。您可以在Pub网站上找到http软件包的最新版本。

dependencies:
  http: <latest_version>

要执行GET操作，请调用http.get（），

http.get("http://api.urbandictionary.com/v0/define?term=api").then(
  (response) // Server response
    {
      if(response.statusCode==200) // Checking if the transaction was successful
        {
          print(response.body);// Your response body
        }
       else print("The transaction was unsuccessful");
    }
);

如果您想解析json请求，

https://flutter.dev/docs/cookbook/networking/background-parsing

参考：https://flutter.dev/docs/cookbook/networking/fetch-data

Answer 3

Future loadUser() async{

    final response = await  http.get(url, 
        headers : { HttpHeaders.contentTypeHeader: 'application/json' }
        Map<String,dynamic> parsedJson = json.decode(response.body);
        body : User.fromJson(parsedJson); 
    );
}

我怎样才能从json中获得响应

3 个答案: