比方说,我有一个swiftui视图,其中显示了按部门划分的员工列表,如何删除该部分中的项目? 向左滑动即可删除uitableview中的行为。
import SwiftUI
struct ContentView: View {
var data: [String : [String]] = ["DeptA": ["EmpA", "EmpB", "EmpC"], "DeptB": ["EmpD", "EmpE", "EmpF"]]
var body: some View {
NavigationView {
List {
ForEach(data.keys.map { String($0) }, id: \.self) { dept in
Section(header: Text(dept)) {
ForEach(self.data[dept]!, id: \.self) { emp in
Text(emp)
}.onDelete(perform: self.deleteEmp)
}
}
}
.navigationBarTitle("Employees")
}
}
private func deleteEmp(indexSet: IndexSet) {
print(indexSet.first!)
}
}
struct ContentView_Previews: PreviewProvider {
static var previews: some View {
ContentView()
}
}
答案 0 :(得分:1)
从数据源中删除它:
struct ContentView: View {
@State var dataSource = ["1", "2", "3", "4"]
var body: some View {
List(dataSource, id: \.self) { number in
Text("Click Here to delete this row " + number)
.onTapGesture {
let index = self.dataSource.firstIndex(of: number)!
self.dataSource.remove(at: index)
}
}
}
}
将二人组更新为您的代码
您将数据源嵌套在两个ForEach
中。第一个可以访问节,第二个可以访问行。所以:
struct ContentView: View {
var data: [String : [String]] = ["DeptA": ["EmpA", "EmpB", "EmpC"],
"DeptB": ["EmpD", "EmpE", "EmpF"]]
var sections: [String] { data.keys.map { $0 } }
func rows(section: Int) -> [String] { data[sections[section]]! }
var body: some View {
NavigationView {
List {
ForEach(0..<sections.count, id: \.self) { section in
Section(header: Text(self.sections[section])) {
ForEach(self.rows(section: section), id: \.self) { emp in
Text(emp)
}.onDelete { row in
self.deleteEmp(section: section, row: row)
}
}
}
}.navigationBarTitle("Employees")
}
}
private func deleteEmp(section: Int, row: IndexSet) {
print("Section:", section)
print("Row:", row.first!)
}
}
请注意,我使用了一些辅助变量和函数。