Question

我想删除String值中的空格，例如：“ I skd a efju N”到“ IdskdaefjuN”，但它不起作用...

我尝试使用：

stringValue = strings.Replace(stringValue, " ", "", -1)

package main

import (
    "fmt"
    "strings"
)

func main() {
    //var String
    var stringValue string
    var originalValue string
    fmt.Printf("please, type some text:")
    //user input
    fmt.Scan(&stringValue)
    originalValue = stringValue
    //remove spaces
    stringValue = strings.Replace(stringValue, " ", "", -1)
    //set string to lower case
    stringValue = strings.ToLower(stringValue)
    //if contains substring "i", "a" and "n"
    if strings.Contains(stringValue, "i") && strings.Contains(stringValue, "a") && strings.Contains(stringValue, "n") {
        // if "i" is a prefix and "n" a suffix
        firstChar := strings.HasPrefix(stringValue, "i")
        lastChar := strings.HasSuffix(stringValue, "n")
        switch {
        //if is a prefix and suffix so Found
        case firstChar && lastChar:
            fmt.Printf("Found in %s", originalValue)
        //if isnt a prefix and suffix so Not Found
        default:
            fmt.Printf("Not Found in %s", originalValue)
        }
        //if there's no "i", "a" and "n"
    } else {
        fmt.Printf("Not Found in %s", originalValue)
    }
}

Answer 1

如何在Go中删除空白

例如，

package main

import (
    "fmt"
    "unicode"
)

func removeSpace(s string) string {
    rr := make([]rune, 0, len(s))
    for _, r := range s {
        if !unicode.IsSpace(r) {
            rr = append(rr, r)
        }
    }
    return string(rr)
}

func main() {
    s := "I d skd a efju N"
    fmt.Println(s)
    s = removeSpace(s)
    fmt.Println(s)
}

游乐场：https://play.golang.org/p/KoXZ24WXw7r

输出：

I d skd a efju N
IdskdaefjuN

Answer 2

当我尝试运行您的代码时，无法使用fmt.Scan()从stdin正确读取。如果将其替换为从stdin读取的缓冲读取器，则它可以正常工作：

package main

import (
    "bufio"
    "fmt"
    "os"
    "strings"
)

func main() {
    //var String
    var stringValue string
    var originalValue string
    reader := bufio.NewReader(os.Stdin)
    fmt.Printf("please, type some text:")
    //user input
    stringValue, _ = reader.ReadString('\n')
    stringValue = strings.TrimSuffix(stringValue, "\n")
    originalValue = stringValue
    //remove spaces
    stringValue = strings.ReplaceAll(stringValue, " ", "")
    //set string to lower case
    stringValue = strings.ToLower(stringValue)
    //if contains substring "i", "a" and "n"
    if strings.Contains(stringValue, "i") && strings.Contains(stringValue, "a") && strings.Contains(stringValue, "n") {
        // if "i" is a prefix and "n" a suffix
        firstChar := strings.HasPrefix(stringValue, "i")
        lastChar := strings.HasSuffix(stringValue, "n")
        switch {
        //if is a prefix and suffix so Found
        case firstChar && lastChar:
            fmt.Printf("Found in %s", originalValue)
        //if isnt a prefix and suffix so Not Found
        default:
            fmt.Printf("Not Found in %s", originalValue)
        }
        //if there's no "i", "a" and "n"
    } else {
        fmt.Printf("Not Found in %s", originalValue)
    }
}

Answer 3

这对我有用

package main

import (
    "fmt"
    "strings"
)
func main() {

    x := "       1    ,2,   3,4,6     -3   0, 7,   8,70   -9   0"
    x = strings.Replace(x, " ", "", -1)
    fmt.Println(x)
}

只需将空格替换为空字符串，请参阅此处的官方 documentation

如何在Go中删除空格

3 个答案: