Question

当我将此二进制转换为十进制时：

0100000101101100011010010010000001000001011010000110110101100101011001000010000001001111011100110110110101100001000010110111000100000011000100100100100110011001001110100011010000110010001100001011101000110010100101101100010001001011010011001100101101101100100100110110100110110100110110110110110110110110110110100110110110110110110100110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110110100110110110110110100

使用VB.Net，我得到这个双重数字：three。

我需要将其格式化为普通数字，如下所示：

10069595034014783469636931351646363690636553221072125712116008033168565762469882090200055592025448896479090348155246

如何使用PHP或VB.Net做到这一点？

1.00695950340148E+115

输出为：

Visual Basic.Net编译器版本0.0.0.5943（Mono 4.7-tarball）
  版权所有（C）2004-2010 Rolf Bjarne Kvinge。保留所有权利。
  程序集'jdoodle，Version = 0.0，Culture = neutral，PublicKeyToken = null'   已成功保存到“ /home/jdoodle.exe”。编译成功
  编译时间为00：00：01.1970230
  x和y的和= 1.00695950340148E + 115

Answer 1

请尝试使用此方法，但我尚未验证它是否正确：

Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
    Dim myBin = "110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111110101010100001111101010101010101000000110110101100000010111"
    Debug.Print(ConvBinToDec(myBin))
End Sub

Function ConvBinToDec(ByVal theVal As String)
    ConvBinToDec = ""
    Dim BinVal(Len(theVal)) As String
    BinVal(1) = "1"
    Dim Total = "0"
    If Mid(theVal, Len(theVal), 1) = "1" Then Total = "1"
    Dim myLast As String = ""
    For a = 2 To Len(theVal)
        BinVal(a) = Multi(BinVal(a - 1))
        myLast = BinVal(a)
        If Mid(theVal, Len(theVal) - a + 1, 1) = "1" Then
            Total = Adding(Total, myLast)
        End If
    Next
    ConvBinToDec = Total

End Function

Function Multi(ByVal TheVal As String) As String
    Dim simpan As Byte = 0
    Multi = ""
    Dim myLen As Byte = 10
    Dim myTimes = -Int(-Len(TheVal) / myLen)

    For a = 1 To myTimes
        Dim myStr As String = Strings.Right(TheVal, a * myLen)
        Dim myRemain As String = Strings.Left(myStr, Len(myStr) - (a - 1) * myLen)
        Multi = Strings.Right("0000000000" & CLng(myRemain) * 2 + simpan, myLen) & Multi
        If Len(CStr(CLng(myRemain) * 2 + simpan)) > myLen Then simpan = 1 Else simpan = 0
        If a = myTimes And simpan = 1 Then Multi = "1" & Multi
    Next
End Function

Function Adding(ByVal TheVal1 As String, ByVal TheVal2 As String) As String
    Dim simpan As Byte = 0
    Adding = ""
    Dim myLen As Byte = 10
    Dim myTimes = -Int(-Len(TheVal2) / myLen)
    TheVal1 = Strings.Right("00000000000" & TheVal1, Len(TheVal2))
    For a = 1 To myTimes
        Dim myStr1 As String = Strings.Right(TheVal1, a * myLen)
        Dim myStr2 As String = Strings.Right(TheVal2, a * myLen)
        Dim myRemain1 As String = Strings.Left(myStr1, Len(myStr1) - (a - 1) * myLen)
        Dim myRemain2 As String = Strings.Left(myStr2, Len(myStr2) - (a - 1) * myLen)
        Adding = Strings.Right("0000000000" & CLng(myRemain1) + CLng(myRemain2) + simpan, myLen) & Adding
        If Len(CStr(CLng(myRemain1) + CLng(myRemain2) + simpan)) > myLen Then simpan = 1 Else simpan = 0
        If a = myTimes And simpan = 1 Then Adding = "1" & Adding
    Next
End Function

当我尝试使用您的二进制文件时，

  "010000010110110001101001001000000100000101101000011011010110010101100100001000000100111101110011011011010110000101101110001000000110001001101001011100100111010001101000011001000110000101110100011001010011101000110001001011010011001100101101001100010011100100111000001101110010000001100011011011110111010101101110011101000111001001111001001110100111001101110101011001000110000101101110"

结果是：

"000010069595034014783469636931351646363690636553221072125712116008033168565762469882090200055592025448896479090348155246"

如何将十进制格式转换为数字格式

1 个答案: