Question

我是mulesoft和Java的新手，正在尝试将blob插入oracle。它将引发错误“无效的列类型”。

下面是我来自mulesoft anypoint 7.3的代码。

package practice_api_design;

import java.io.UnsupportedEncodingException;
import java.sql.Blob;
import java.sql.SQLException;
import javax.sql.rowset.serial.SerialBlob;
import javax.sql.rowset.serial.SerialException;

public class Base64ToBlob {

    public String b = "";

    public Base64ToBlob(String base64Str) {
        b = (String) base64Str;
    }

    public Blob byteArrToBlob(String b) throws SerialException, SQLException, UnsupportedEncodingException {
        Blob blob = null;
        byte[] byteArr = b.getBytes();
        blob = new SerialBlob(byteArr);
        return blob;
    }
}

这是来自mulesoft的项目配置。

<flow name="uploadDocuments" doc:id="0a5e9e1d-a5d9-48af-959b-3c8292f3aff8" >
        <http:listener doc:name="Upload documents" doc:id="ab922884-b2f4-4c49-a14a-8a6e48f26266" config-ref="Global_Listener" path="/uploadDocs"/>
        <ee:transform doc:name="Transform Message" doc:id="70408165-9d05-412b-906a-bd1c8cb30df9" >
            <ee:message >
                <ee:set-payload ><![CDATA[%dw 2.0
output application/json
---
[
    {
        name: payload.name,
        mimeType: payload.mimeType,
        dadCharset: payload.dadCharset,
        contentType: payload.contentType,
        base64Str: payload.base64Str,
        description: payload.description,
        username: payload.username
    }
]]]></ee:set-payload>
            </ee:message>
        </ee:transform>
        <set-variable value="#[{
    name: payload[0].name[0],
    mimeType: payload[0].mimeType[0],
    dadCharset: payload[0].dadCharset[0],
    contentType: payload[0].contentType[0],
    base64Str: payload[0].base64Str[0],
    description: payload[0].description[0],
    username: payload[0].username[0]
}]" doc:name="Set Variable" doc:id="1ee41214-5534-4f71-ad43-41c3e0a96817" variableName="jsonObj"/>
        <java:new constructor="Base64ToBlob(java.lang.String)" doc:name="New" doc:id="4f1400d5-c453-43e8-beb3-1b3a8191f208" class="practice_api_design.Base64ToBlob">
            <java:args ><![CDATA[#[{
    base64Str: payload[0].base64Str[0] 
}]]]></java:args>
        </java:new>
        <java:invoke method="byteArrToBlob(java.lang.String)" doc:name="Invoke" doc:id="88592758-6fe1-4f09-a56e-dfc57760111f" instance="#[payload]" class="practice_api_design.Base64ToBlob" target="blob">
            <java:args ><![CDATA[#[{
    b: vars.jsonObj.base64Str
}]]]></java:args>
        </java:invoke>
        <db:insert doc:name="Insert" doc:id="f1b53033-7dda-49f8-ae70-81b0b2e72607" config-ref="ELS_Blue">
            <db:sql >insert into 
    app_wag.stdprosp_files
        (
            name, 
            blob_content
        ) 
    values 
        (
            :name, 
            :blob
        )</db:sql>
            <db:input-parameters ><![CDATA[#[{
    name: vars.jsonObj.name,
    blob: vars.blob
}]]]></db:input-parameters>
        </db:insert>
        <logger level="INFO" doc:name="Logger" doc:id="6068e02b-6c29-44f5-af76-849652a2f7ae" message="#[vars.blob]" />
    </flow>

并在插入时抛出。.

Invalid column type

检查了oracle并确认该列的数据类型为'BLOB'，我认为它会接受任何类型为BLOB的值。

对此有任何想法或想法吗？

在Oracle中插入Blob

0 个答案: