Question

我有一个具有数据时间和个人身份的表，我想在其中查找每天时间之间的时差并在SQL中求平均值。

输入表

    +---------------------+----------+--------+
    |      Datetime       | Identity |  Type  |
    +---------------------+----------+--------+
    | 28/08/2019 4:00:00  | ABC      | Entry  |
    | 28/08/2019 14:00:00 | ABC      | Exit   |
    | 29/08/2019 6:00:00  | ABC      | Entry  |
    | 29/08/2019 6:10:00  | ABC      | Exit   |
    | 30/08/2019 8:00:00  | ABC      | Entry  |
    | 30/08/2019 17:00:00 | ABC      | Exit   |
    +---------------------+----------+--------+

是否可以使用SQL中的以下数据创建另一个表？

    +------------+----------+-----------+
    |    Date    | Identity | Time(Min) |  
    +------------+----------+-----------+
    | 28/08/2019 | ABC      |       600 |  
    | 29/08/2019 | ABC      |        10 |  
    | 30/08/2019 | ABC      |       540 |  
    +------------+----------+-----------+

谢谢。

Answer 1

您可以在下面尝试-适用于mysql

{
  "author": "Robin Sharma",
  "data": [
    {
      "translation": "en",
      "content": "foo",
      "unwanted_content": "huyu1",
    },
  ],
}

或sql服务器-

select cast(datetime as date), 
       TIMESTAMPDIFF(MINUTE,min(case when Type='Entry' then datetime end),
       max(case when Type='Exit' then datetime end))
from tablename
group by cast(datetime as date)

Answer 2

我认为这应该可以在SQL Server中满足您的需求：

assistive_technologies=org.GNOME.Accessibility.AtkWrapper

如何在SQL中找到两个日期时间行的平均时间？

2 个答案: