我有一个采用UTM和其他url参数的JS代码,因此当用户在页面之间导航时,我不会迷路。当href是页面时,该代码可以很好地工作,而当它与id元素相关时,代码则不能工作
我试图在if语句中排除它,或者在id后面添加参数。
function getRefQueryParam(name) {
name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
var results = regex.exec(location.search);
return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
};
var utmParamQueryString = '',
utmParamQueryStringTrimmed = '',
utm_source = '',
utm_medium = '',
utm_content = '',
utm_campaign = '',
utm_term = '';
(function() {
utm_source = getRefQueryParam("utm_source");
utm_medium = getRefQueryParam("utm_medium");
utm_content = getRefQueryParam("utm_content");
utm_campaign = getRefQueryParam("utm_campaign");
utm_term = getRefQueryParam("utm_term");
gclid = getRefQueryParam("gclid");
fbclid = getRefQueryParam("fbclid");
if (utm_source) {
utmParamQueryString += '&utm_source=' + utm_source;
}
if (utm_medium) {
utmParamQueryString += '&utm_medium=' + utm_medium;
}
if (utm_content) {
utmParamQueryString += '&utm_content=' + utm_content;
}
if (utm_campaign) {
utmParamQueryString += '&utm_campaign=' + utm_campaign;
}
if (utm_term) {
utmParamQueryString += '&utm_term=' + utm_term;
}
if (gclid) {
utmParamQueryString += '&gclid=' + gclid;
}
if (fbclid) {
utmParamQueryString += '&fbclid=' + fbclid;
}
if(utmParamQueryString.length > 0) {
utmParamQueryString = utmParamQueryString.substring(1);
utmParamQueryStringTrimmed = utmParamQueryString;
utmParamQueryString = utmParamQueryString;
}
if (!utmParamQueryString) return;
var navLinks = document.querySelectorAll('a');
navLinks.forEach(function(item) {
if (item.href.indexOf('/') === 0 || item.href.indexOf(location.host) !== -1 ) {
if (item.href.indexOf('?') === -1) {
item.href += '?';
} else {
item.href += '&';
}
item.href += utmParamQueryString;
}
});
})();
因此它将搜索每个锚标记,并且在页面uri之后,代码将插入当前URL所具有的参数。问题在于它甚至会插入ID调用<a href="#top"></a>
之类的代码,并且该调用不再起作用,因为参数不是在参数插入之后而是在参数插入之间插入,如下所示:
utm_source = google&utm_medium = cpc&utm_campaign = test_cpc&utm_term = test #top &utm_source = google&utm_medium = cpc&utm_campaign = test_cpc&utm_term = test
答案 0 :(得分:4)
您可以尝试在querySelectorAll
上使用attribute selector,如下所示:
document.querySelectorAll('a:not([href^="#"])')
这将选择a
属性不是以href
开头的所有#
标签。
您当然可以尝试根据需要进行修改。