Question

我正在尝试测试端点，但收到400错误的请求错误说明：由于某些被认为是客户端错误的原因（例如格式错误的请求语法，无效的请求消息框架或欺骗性的请求路由），服务器无法或不会处理该请求。

我正在使用spring，hibernate和JPA。

我感觉好像我在看东西，我需要另一双眼睛。

我正在邮递员中传递此信息：

   {
        "macAddress":{
                    "userId": 43,
                    "username": "username",
                    "password": "password",
                    "firstName": "firstname",
                    "lastName": "lastname",
                    "macAddress": "macaddress"},
        "ssid": "ssid",
        "ssidPassword": "ssidpassword"
    }

RDKAcces.java：

@Entity
@Table(name="RDKAccess", schema="db")
public class RDKAccess implements Serializable {

private static final long serialVersionUID = 1L;

    @JoinColumn(name="MAC_Address")
    @OneToOne
    @Id
    private User macAddress;

    @Column(name="SSID")
    private String ssid;

    @Column(name="SSID_Password")
    private String ssidPassword;

    public RDKAccess(User macAddress, String ssid, String ssidPassword) {
        super();
        this.macAddress = macAddress;
        this.ssid = ssid;
        this.ssidPassword = ssidPassword;
    }
...

User.java：


@Entity
@Table(name="User", schema="db", uniqueConstraints = {@UniqueConstraint(columnNames= "Username")})
public class User implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @Column(name="User_Id")
    private Integer userId;

    @Column(name="Username", unique=true)
    private String username;

    @Column(name="Password")
    private String password;

    @Column(name="First_Name")
    private String firstName;

    @Column(name="Last_Name")
    private String lastName;

    @Column(name="MAC_Address", unique=true)
    private String macAddress;


    @OneToMany(mappedBy = "guestId", fetch = FetchType.EAGER)
    private Set<Reservation> guestReservations = new HashSet<>();

    @OneToMany(mappedBy= "hostId", fetch = FetchType.EAGER)
    private Set<Reservation> hostReservations = new HashSet<>();

    @OneToOne(mappedBy="macAddress", fetch = FetchType.EAGER)
    private RDKAccess userMAC;



    public User(Integer userId, String username, String password, String firstName, String lastName, String macAddress,
            Set<Reservation> guestReservations, Set<Reservation> hostReservations) {
        super();
        this.userId = userId;
        this.username = username;
        this.password = password;
        this.firstName = firstName;
        this.lastName = lastName;
        this.macAddress = macAddress;
        this.guestReservations = guestReservations;
        this.hostReservations = hostReservations;
    }
....

RDKAccessController.java

@Controller
@RequestMapping("/RDK")
@CrossOrigin(origins="*", allowedHeaders="*", value="*")
public class RDKAccessController {

    @Autowired
    RDKAccessService rdkServ;

    @PostMapping(value="/add")
    @ResponseBody
    public void add(@RequestBody RDKAccess access) {
        rdkServ.add(access);
    }
...

我想做的是使用ssid和ssidpassword将macaddress添加到数据库中的表中（该Mac Address应该与用户传递的信息具有一对一的关系，但这不起作用如果可以帮助您，请在此处找到该问题Can I map a single column to two tables at one time?的链接）。

我只希望能够将这些值传递到我的数据库中，却无法弄清楚通话中出了什么问题。

如何解决400错误请求

0 个答案: