Type TableName TableRowCount
Source table_1 1
Destination table_1 3
Source table_2 10
Destination table_2 5
SourceTableName SourceTableRowCount DestinationTableName DestinationTableRowCount
-------------- ------------------- -------------------- ------------------------
table_1 1 table_1 3
table_2 10 table_2 5
答案 0 :(得分:0)
这是您的查询。
select t1.TableName As SourceTableName, t1.SourceTableRowCount as SrcCnt, t2.TableName as DestinationTableName, t2.TableRowCount as DestinationTableRowCount from test t1
left join test t2 on t2.Type != t1.Type and t2.TableName = t1.TableName
where t2.Type = 'Destination'
答案 1 :(得分:0)
您可以使用inner join
获得所需的结果。首先,根据需要在不同的记录集中过滤结果,然后根据基本值(在这种情况下为tablename
)的联接将它们组合起来。
; with cte as (
select TableName as SourceTableName, TableRowCount as SourceTableRowCount from yourtable
where type = 'source'
)
, ct as (
select TableName as DestinationTableName, TableRowCount as DestinationTableRowCount from yourtable
where type = 'Destination'
)
select * from cte inner join ct on cte.SourceTableName = ct.DestinationTableName