反序列化包含子数组的Json对象

时间:2011-04-24 11:32:04

标签: c# json

我有以下Json字符串(包含subArray):

  

{ “属性”:   [{ “名称”: “一”, “数据”:[ “10”, “0”, “50”], “数据名”:[ “2000248”, “2789290”, “2789291”],   “dataValue”:[ “一”, “B”, “C”], “toClick”: “d”},   { “名称”: “V”, “数据”:[ “0”, “0”, “0”, “20”]   “数据名”:   [ “49500000”, “49500001”, “49500002”, “49500003”],   “dataValue”:[ “一”, “V”, “V”, “d”], “toClick”: “d”}]}“

我无法在csharp中反序列化。 [评论后更新] 我做了什么:

public class attributes
{
    public string name { get; set; }
    public string[] data { get; set; }
    public string[] dataName { get; set; }
    public string[] dataValue { get; set; }
    public string toClick { get; set; }
}


public class DataJsonAttributeContainer
{
    public List<attributes> JsonAttributeAfterSaves { get; set; }
}

public static T DeserializeFromJson<T>(string json)
{
    T deserializedProduct = JsonConvert.DeserializeObject<T>(json, settings);
    return deserializedProduct;
}

private void testJson()
{
    string JsonStr =
        "{\"attributes\":[{\"name\":\"a\",\"data\":[\"10\",\"0\",\"50\"],\"dataName\":[\"2000248\",\"2789290\",\"2789291\"],\"dataValue\":[\"a\",\"a\",\"d\"],\"toClick\":\"d\"},{\"name\":\"d\",\"data\":[\"0\",\"0\",\"0\",\"20\"],\"dataName\":[\"49500000\",\"49500001\",\"49500002\",\"49500003\"],\"dataValue\":[\"a\",\"a\",\"d\",\"d\"],\"toClick\":\"a\"}]}";
    var container = DeserializeFromJson<DataJsonAttributeContainer>(JsonStr);
}

测试方法:

testJson()

我该怎么办?

2 个答案:

答案 0 :(得分:2)

根据您的JSON,DataJsonAttributeContainer中的您的属性名称错误。这是一个尽我所知的例子:

using System;
using System.Collections.Generic;
using Newtonsoft.Json;

public class Attributes
{
    public string name { get; set; }
    public string[] data { get; set; }
    public string[] dataName { get; set; }
    public string[] dataValue { get; set; }
    public string toClick { get; set; }
}


public class DataJsonAttributeContainer
{
    public List<Attributes> attributes { get; set; }
}

class Test
{

    public static T DeserializeFromJson<T>(string json)
    {
        T deserializedProduct = JsonConvert.DeserializeObject<T>(json);
        return deserializedProduct;
    }

    static void Main()
    {
        string JsonStr =
            "{\"attributes\":[{\"name\":\"a\",\"data\":[\"10\",\"0\",\"50\"],\"dataName\":[\"2000248\",\"2789290\",\"2789291\"],\"dataValue\":[\"a\",\"a\",\"d\"],\"toClick\":\"d\"},{\"name\":\"d\",\"data\":[\"0\",\"0\",\"0\",\"20\"],\"dataName\":[\"49500000\",\"49500001\",\"49500002\",\"49500003\"],\"dataValue\":[\"a\",\"a\",\"d\",\"d\"],\"toClick\":\"a\"}]}";
        var container = DeserializeFromJson<DataJsonAttributeContainer>(JsonStr);
        Console.WriteLine(container.attributes.Count); // Prints 2
        Console.WriteLine(container.attributes[0].data.Length); // Prints 3
    }
}

答案 1 :(得分:0)

您必须指定正确的类型,如果是DataJsonAttributeContainer,则必须指定正确的属性名称:

public class attributes
{
    public string name { get; set; }
    public int[] data { get; set; }
    public int[] dataName { get; set; }
    public string[] dataValue { get; set; }
    public string toClick { get; set; }
}

public class DataJsonAttributeContainer
{
    public List<attributes> attributes { get; set; }
}

使用之前的定义,以下内容适合我(在我从JSON字符串中删除最后一个"之后):

var data = JsonConvert.DeserializeObject<DataJsonAttributeContainer>(jsonString);