为什么我的服务会自动启动和停止？

Question

我使用 Python 3.7 编写窗口服务。我使用此命令安装了服务

python myservice.py install

然后它出现在services.msc中，但是当我尝试启动时出现此错误。

当我使用此代码调试服务时

python myservice.py debug

我得到了这个回报：

C:\WINDOWS\system32>python C:\Users\lenovo\Desktop\py\Service.py debug
Debugging service Service- press Ctrl+C to stop.
Error 0xC0000003 - The instance's SvcRun() method failed

<Error getting traceback - traceback.print_exception() failed

(null): (null)

我搜索并尝试了Internet上的所有方法，但无法解决。 win32service可能包含错误吗？我该如何解决这个问题？

我的python脚本：

import win32event 
import win32serviceutil
import servicemanager
import win32service
import uuid,re
import socket
import time

class Service(win32serviceutil.ServiceFramework):
  try:
    _svc_name_ = "Service"
    _svc_display_name_ = "Service"
    _svc_description_ = "Service"
    def __init__(self,args):
        win32serviceutil.ServiceFramework.__init__(self,args)
        self.hWaitStop = win32event.CreateEvent(None,0,0,None)
        socket.setdefaulttimeout(60)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
                              servicemanager.PYS_SERVICE_STOPPED,
                              (self._svc_name_,''))
        self.stop()


    def SvcDoRun(self):
        self.run()
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
                              servicemanager.PYS_SERVICE_STARTED,
                              (self._svc_name_,''))

        self.main()


    def stop(self):
      self.isrunning=False
      pass
    def start(self):
      self.isrunning=True
      pass
    def main(self):

        while self.isrunning:
            time.sleep(5)
            servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
                              "RUNNING",
                              (self._svc_name_,''))
             #there were my socket codes

    def parse_command_line():
            win32serviceutil.HandleCommandLine(Service)

  except:
   print("error")         



if __name__ == '__main__':

   Service.parse_command_line()