Question

对于给定的场景，我无法找到解决方案，因为我有一个多维数组，必须在其中找到具有相同ID的数组的值之和。

demo.php

$array = array("1"=>array("id"=>"1", "total"=>"100"),
                "2"=>array("id"=>"2", "total"=>"300"),
                "3"=>array("id"=>"3", "total"=>"400"),
                 "4"=>array("id"=>"4", "total"=>"500"),
                 "5"=>array("id"=>"1", "total"=>"560"));

我想获取所有重复ID的总数，例如1是该ID，总数为100 + 560 = 650。

Answer 1

一种选择是使用array_reduce将数组汇总为一个关联数组。

$array = //....

$result = array_reduce( $array, function( $c, $v ){

    if ( !isset( $c[ $v["id"] ] ) ) $c[ $v["id"] ] = 0;
    $c[ $v["id"] ] += $v["total"];

    return $c;
}, array() );

$result将是：

Array
(
    [1] => 660
    [2] => 300
    [3] => 400
    [4] => 500
)

更新

添加另一个reduce以首先对数组进行分组。第二个reduce仅包含具有多个计数的数组元素。

$array = //....
$group = array_reduce( $array, function( $c, $v ){
    if ( !isset( $c[ $v["id"] ] ) ) $c[ $v["id"] ] = [ "count" => 0, "total" => 0, "id" => $v["id"] ];
    $c[ $v["id"] ]["count"] += 1;
    $c[ $v["id"] ]["total"] += $v["total"];
    return $c;
}, array() ); 

$result = array_reduce( $group, function( $c, $v ){
    if ( $v["count"] > 1 ) $c[ $v["id"] ] = $v["total"];
    return $c;
}, array() );

这将导致：

Array
(
    [1] => 660
)

Answer 2

使用foreach时的另一种方法：

$array = array("1"=>array("id"=>"1", "total"=>"100"),
            "2"=>array("id"=>"2", "total"=>"300"),
            "3"=>array("id"=>"3", "total"=>"400"),
             "4"=>array("id"=>"4", "total"=>"500"),
             "5"=>array("id"=>"1", "total"=>"560"));

$total = [];

foreach ($array as $sub) {
    $total[$sub['id']] = isset($total[$sub['id']]) ? $total[$sub['id']] += $sub['total'] : $total[$sub['id']] = $sub['total'];
}

输出

Array
(
    [1] => 660
    [2] => 300
    [3] => 400
    [4] => 500
)

实时示例

Repl

阅读材料

Ternary Operator

Answer 3

您可以使用简单的foreach循环来获得预期的结果

<?php
// Your code here!
$array = array("1"=>array("id"=>"1", "total"=>"100"),
                "2"=>array("id"=>"2", "total"=>"300"),
                "3"=>array("id"=>"3", "total"=>"400"),
                 "4"=>array("id"=>"4", "total"=>"500"),
                 "5"=>array("id"=>"1", "total"=>"560"));
$issetArray = array();

foreach ($array as $key => $value) {
    if(isset($issetArray[$value['id']]))
    {
        $issetArray[$value['id']]['total'] += $value['total'];
    }
    else
    {
        $issetArray[$value['id']] = array();
        $issetArray[$value['id']] = $value;
    }
}

$result = array();
foreach ($issetArray as $value) {
    array_push($result, $value);
}

print_r($result);
?>

示例：https://paiza.io/projects/Fnay-hbk4Cuf_-rMTL5AFA

Answer 4

如果您要使用外部类tableArray，并且想要保留输入数组的结构，请尝试以下操作：

$array = array("1"=>array("id"=>"1", "total"=>"100"),
                "2"=>array("id"=>"2", "total"=>"300"),
                "3"=>array("id"=>"3", "total"=>"400"),
                 "4"=>array("id"=>"4", "total"=>"500"),
                 "5"=>array("id"=>"1", "total"=>"560"));

$newData = tableArray::create($array)
  ->filterGroupSum('total',['id'])
  ->fetchAll()
;

$ newData：

array (
  0 => 
  array (
    'id' => "1",
    'total' => 660,
  ),
  1 => 
  array (
    'id' => "2",
    'total' => 300,
  ),
  2 => 
  array (
    'id' => "3",
    'total' => 400,
  ),
  3 => 
  array (
    'id' => "4",
    'total' => 500,
  ),
)

查找在PHP中具有重复值的键的值的总和

4 个答案: