Question

我正在遍历目录以更新某些工作簿中的外部链接，然后将其目的是使csv脱离这些工作簿。我有它的功能，但没有将.csv文件后缀获取名称和路径，而是将.csv添加到.xlsx

import os
import csv
import xlrd
import win32com.client

directory = (r'D:\\Dropbox (DBM Vircon)\\XX_Share Internal\\190826 - CD Refresh and Output CSVs')
suffix = '.csv'

for file in os.listdir(directory):
    filename = os.fsdecode(file)
    if filename.endswith(".xlsx"):

        wb = os.path.join(directory, filename)
        print (wb)
        clean = os.path.splitext(wb)
        xlapp = win32com.client.DispatchEx("Excel.Application")
        wb1 = xlapp.workbooks.open(wb)
        xlapp.Visible = False
        wb1.RefreshAll()
        print("refreshed")
        wb1.Save()
        xlapp.Quit()
        print("finished")


        wb1 = xlrd.open_workbook(wb)
        sh = wb1.sheet_by_index(0)
#Below just adds .csv to filename instead of getting name, then adding it 
        mycsv = os.path.join(directory, filename + suffix)
        mynewcsv = open(mycsv, 'w', newline='')
        wr = csv.writer(mynewcsv, quoting=csv.QUOTE_ALL)
        for rownum in range(sh.nrows):
            wr.writerow(sh.row_values(rownum))

        #mycsv.close()

        continue
    else:
        continue

file_obj = open("CSVUpdatecomplete.csv", 'w')

Answer 1

使用os.path.splitext将名称与扩展名分开：

...
name, ext = os.path.splitext(filename)
mycsv = os.path.join(directory, name + suffix)
...

Answer 2

由于filename的末尾包含.xlsx，因此您将要替换为.csv而不是附加。

例如，使用filename.replace('.xlsx', '.csv')代替filename + suffix

Answer 3

您可以仅对文件名使用分割功能：

Name    M/F Grade   Size    Notes
0   Peter Parker    M   1/2 YM  Baughman
1   Tony Stark  M   1/2 YL  Baughman
2   Steve Rogers    M   1/2 YM  Baughman
3   Donald Blake    M   1/2 YM  Baughman
4   Bruce Banner    M   3/4 YM  Baughman

Python循环从目录

3 个答案: