Question

我对Spring Security（总体而言是安全性）不熟悉，因此我尝试创建一个成功登录后进入产品页面的用户登录。在学习了有关安全性配置的所有教程之后，我不断出现“登录？错误”，我想不通为什么，我无法在调试器中查明原因。

我正在使用Postgresql，并具有表user，role，user_role。我已经验证了jdbcAuthentication的sql语句，并以多种不同方式配置了.formLogin

下面是我的Web安全配置，登录控制器和登录视图。谁能告诉我我做错了吗？谢谢。

SpringSecurityConfig.java


import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder;
import org.springframework.security.crypto.password.PasswordEncoder;
import org.springframework.security.web.access.AccessDeniedHandler;

import javax.sql.DataSource;

@Configuration
@EnableWebSecurity
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {


    @Autowired
    private DataSource dataSource;


    @Autowired
    public void configAuthentication(AuthenticationManagerBuilder auth) throws Exception {

        // Database authentication
        auth.
                jdbcAuthentication()
                .dataSource(dataSource)
                .usersByUsernameQuery("SELECT username, password, active FROM \"user\" WHERE username = ?")
                .authoritiesByUsernameQuery("SELECT u.username, r.role FROM \"user\" u join user_role ur on (u.userid=ur.userid) join role r on (ur.roleid=r.roleid) WHERE u.username = ?");

    }


    @Override
    protected void configure(HttpSecurity http) throws Exception {

        http
                .authorizeRequests()
                .antMatchers("/products","/mycart","/images/**").permitAll()
                .anyRequest().authenticated()
                .and()
                .formLogin()
                .loginPage("/login")
                .successForwardUrl("/products")
                .usernameParameter("username")
                .passwordParameter("password")
                .permitAll()
                .and()
                .logout()
                .permitAll();

    }

    @Bean
    public PasswordEncoder passwordEncoder(){
        return new BCryptPasswordEncoder();
    }


}

LoginController.java

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.*;
import java.security.Principal;

@Controller
public class LoginController {

    @RequestMapping(value = {"/", "/login"}, method = RequestMethod.GET)
    public String loginView(Principal principal) {

        return "/login";
    }
}

login.html

<html lang="en" xmlns:th="http://www.thymeleaf.org">

<head>
    <meta charset="UTF-8">
    <title>Login</title>
</head>
<body>
<div>
    <form th:action="@{/login}" method="POST">

        <div th:if="${param.error}">
            <div class="alert alert-danger">
                Incorrect Username and Password
            </div>
        </div>

        <div th:if="${param.logout}">
            <div class="alert alert-danger">
                User Logged Out
            </div>
        </div>

        <div class="form-group">
            <input type="text" placeholder="Username" id="username" class="form-control" required="true" autofocus="true"/>
        </div>

        <div class="form-group">
            <input type="password" placeholder="Password" id="password" class="form-control" required="true" autofocus="true"/>
        </div>

        <div>
            <input type="submit" class="btm btm-primary btn-block" value="Login"/>
        </div>
    </form>

    <a href="/registration">Register</a>
</div>

</body>
</html>

Answer 1

您的配置看起来不错，但您需要像这样在输入中添加“名称”属性：

<div class="form-group">
    <input type="text" placeholder="Username" id="username" name="username" class="form-control" required="true" autofocus="true"/>
</div>

<div class="form-group">
    <input type="password" placeholder="Password" id="password" name="password" class="form-control" required="true" autofocus="true"/>
</div>

第二，检查您是否已使用BCryptPasswordEncoder在数据库中对密码进行编码（或首先尝试在没有编码器的情况下设置普通密码）。

以另一种方式尝试在github中提交示例项目，也许我可以为您提供帮助。

Spring Security登录显示错误页面，身份验证失败？

1 个答案: