Question

我尝试了此操作，但由于24小时周期而无法正常工作：

const isBetweenHours = (currentHour, startHour, endHour) => {
  if (currentHour >= startHour && currentHour <= endHour) {
    return true
  }
  return false
}

有效的示例：

currentHour = 7 // 7AM
startHour = 10 // 10AM
endHour = 18 // 6PM
isBetweenHours(currentHour, startHour, endHour)

失败的示例：

currentHour = 22 // 10PM
startHour = 21 // 9PM
endHour = 4 // APM
isBetweenHours(currentHour, startHour, endHour)

Answer 1

如果结束时间小于开始时间，那么我们就在第二天，因此加24以获得真实的照片：

const isBetweenHours = (currentHour, startHour, endHour) => {
  if (endHour < startHour) { endHour += 24; }
  if (currentHour >= startHour && currentHour <= endHour) {
    return true
  }
  return false
}

Answer 2

您的代码应能正常工作：

const isBetweenHours = (currentHour, startHour, endHour) => {
  if (currentHour >= startHour && currentHour <= endHour) {
    return true
  }
  return false
}

// example
currentHour = 7 // 7AM
startHour = 10 // 10AM
endHour = 18 // 6PM
console.log(isBetweenHours(currentHour, startHour, endHour)); // false: 7 is not between 10 and 18

currentHour = 13 // 1PM
startHour = 10 // 10AM
endHour = 18 // 6PM
console.log(isBetweenHours(currentHour, startHour, endHour)); // true: 13 is  between 10 and 18

currentHour = 18 // 6PM
startHour = 10 // 10AM
endHour = 18 // 6PM
console.log(isBetweenHours(currentHour, startHour, endHour)); // true: 18 is between 10 and <=18

如果小时A在小时B与小时C之间如何获取？

2 个答案: