我有一个指向Event对象的指针向量,如下所示:
std::vector <Event*> event_queue_;
这是我的活动课程
class Event{
...
bool IsAlarmSensitiveEvent();
bool alarm_sensitive_event_;
...
};
当alarm_sensitive_event_为true时,我想从指针和事件对象的向量中删除指针。
我试图这样做:
for (Event* x : event_queue_)
{
if (x != nullptr)
{
for (int i = 0; i < event_queue_.size(); i++)
{
if (event_queue_.at(i)->IsAlarmSensitiveEvent())
{
std::cout << "Removing event " << event_queue_.at(i)->NameOfEvent() << std::endl;
delete event_queue_.at(i);
event_queue_.erase(event_queue_.begin() + i);
removed = true;
}
}
}
}
它正在工作,但是我认为循环并不是最好的方法,所以我正在寻找更好的东西。
答案 0 :(得分:1)
使用this answer作为指导,您可以划分元素以首先删除,删除它们,然后从矢量中删除它们:
#include <vector>
#include <algorithm>
//…
// Partition the elements to delete (place the items to delete on right side of vector)
auto iter = std::stable_partition(event_queue.begin(), event_queue.end(),
[](Event *x) { return !x->IsAlarmSensitiveEvent(); });
// Deallocate them
std::for_each(iter, event_queue.end(), [](Event *x)
{
std::cout << "Removing event " << x->NameOfEvent() << "\n";
delete x;
});
// Erase them from vector
event_queue.erase(iter, event_queue.end());
//...
答案 1 :(得分:0)
如果我拥有auto* event_queue_ = new vector<Event>
而不是vector <Event*> event_queue_
怎么办?