Question

我有一个存储评论的表。注释具有不同的深度级别，并且在具有id和parent_id的一个表中彼此相关。深度级别的最大值是三，我想用一个查询而不是三个查询来选择它们，并使用foreach三次。

评论表：

id title                           parent_id 
 1 'where are you?'                NULL
 2 "im at home"                       1
 3 "what is time in your country?" NULL 
 4 "it's 3 pm"                        3
 5 "oh that's cool"                   4

第一级是具有parent_id = NULL的注释我使用这些查询来获取它们：

$first = $this->db->query("SELECT title FROM comment WHERE parent_id IS NULL");
    $second = $this->db->query("SELECT title FROM comment WHERE parent_id IN (SELECT id FROM comment WHERE parent_id IS NULL)");
        $third= $this->db->query("SELECT title FROM comment WHERE parent_id IN (SELECT id FROM comment WHERE parent_id IN(SELECT id FROM comment WHERE parent_id IS NULL))");

是否可以通过一个查询来获取它们？

Answer 1

您可以创建递归函数/方法，这将为您执行此循环。或使用do-while构造：

$parentIds = null;
do {
    $where = (is_null($parentIds)) ? 'IS NULL' : sprintf('IN (%s)', implode(',', $parentIds));

    $query = $this->db->query("SELECT title FROM comment WHERE parent_id " . $where);

    // Do something with $query data
    // In your process $query loop you must fill $parentIds with `parent_id` column value

    // ...
    $parentIds[] = $row['parent_id'];
    // ...
} while (!empty($parentIds));

Answer 2

SELECT c1.title AS lev1, c2.title as lev2, c3.title as lev3
FROM comment AS C1
LEFT JOIN category AS c2 ON c2.parent_id = c1.id
LEFT JOIN category AS c3 ON c3.parent_id = c2.id
WHERE c1.parent_id IS NULL;

Answer 3

由于级别的最大深度为3，因此我们可以利用两个自联接来确定父级id，并使用自定义排序。

如果您的MySQL / MariaDB版本不支持递归CTE，请尝试以下解决方案：

模式（MySQL v5.7）

CREATE TABLE comment
    (`id` int, `title` varchar(33), `parent_id` varchar(4))
;

INSERT INTO comment
    (`id`, `title`, `parent_id`)
VALUES
    (1, 'where are you?', NULL),
    (2, 'what is time in your country?', NULL),
    (3, 'im at home', '1'),
    (4, 'its 3 pm', '2'),
    (5, 'oh thats cool', '4')
;

查询＃1

SELECT c1.id, c1.title, c1.parent_id 
FROM comment AS c1 
LEFT JOIN comment AS c2 ON c2.id = c1.parent_id 
LEFT JOIN comment AS c3 ON c3.id = c2.parent_id 
ORDER BY 
  CASE WHEN c1.parent_id IS NULL THEN c1.id  /* first level comment*/
       WHEN c2.parent_id IS NULL THEN c2.id  /* second level comment */
       ELSE c3.id /* comment is at third level */
  END ASC, 
  c1.id ASC;

| id  | title                         | parent_id |
| --- | ----------------------------- | --------- |
| 1   | where are you?                |           |
| 3   | im at home                    | 1         |
| 2   | what is time in your country? |           |
| 4   | its 3 pm                      | 2         |
| 5   | oh thats cool                 | 4         |

View on DB Fiddle

选择三个级别的评论

3 个答案: