Question

我需要合并所有作者的特定UID。基本字段正在另一篇文章的代码中工作。

DECLARE @json NVARCHAR(MAX)

SET @json = '{
        "header": {
            "type": "esummary",
            "version": "0.3"
        },
        "result": {
            "uids": [
                "17784783",
                "19505939",
                "30166592"
            ],
            "17784783": {
                "uid": "17784783",
                "pubdate": "2007 Aug",
                "epubdate": "2007 Jul 20",
                "source": "PLoS Comput Biol",          
                "sortpubdate": "2007/08/01 00:00",
                   "authors": [
                {
                    "name": "Yu Y",
                    "authtype": "Author",
                    "clusterid": ""
                },
                {
                    "name": "Wang G",
                    "authtype": "Author",
                    "clusterid": ""
                },
                {
                    "name": "Simha R",
                    "authtype": "Author",
                    "clusterid": ""
                }
                 ]          
            ,
            "19505939": {
                "uid": "19505939",
                "pubdate": "2009 Aug 1",
                "epubdate": "2009 Jun 8",
                "source": "Bioinformatics",          
                "sortpubdate": "2009/08/01 00:00"
                  },
                "authors": [
                {
                    "name": "Zang C",
                    "authtype": "Author",
                    "clusterid": ""
                }],

        "30166592": {
            "uid": "30166592",
            "pubdate": "2019 Jan",
            "epubdate": "2018 Aug 30",
            "source": "Oncogene",
             "sortpubdate": "2019/01/01 00:00",
            "authors": [
            {
                "name": "Sun J",
                "authtype": "Author",
                "clusterid": ""
            },
            {
                "name": "Cai X",
                "authtype": "Author",
                "clusterid": ""
            }],

        }
    }
}'

最后我想结束

uid         sortpubdate         epubdate         Authors
-----------------------------------------------------------------------
17784783    2007/08/01 00:00    2007 Jul 20      Yu Y,Wang G,Simha R
19505939    2009/08/01 00:00    2009 Jun 8       Simha R   
30166592    2019/01/01 00:00    2018 Aug 30      Sun J, Cai, X

我在OPENJSON syntax in a stored procedure in SQL Server 2016的Zohar Peled处得到了一个很好的答复，它对第一部分有所帮助，现在我需要看看能否完成此工作。

SELECT [uid], [sortpubdate], [epubdate]
FROM OPENJSON(@json, N'$.result') AS items
CROSS APPLY
-- parse each object in the array
OPENJSON(items.[value])
WITH(
    [uid] nvarchar(max) N'$.uid' ,
    [sortpubdate] nvarchar(max) N'$.sortpubdate',
    [epubdate] nvarchar(max) N'$.epubdate'
) As content
WHERE [key] <> 'uids' -- Get only the relevant content

Answer 1

您发布的json有点混乱，所以我已经对其进行了编辑。

下一个查询应该使用公用表表达式以及stuff和for xml的组合为您提供包括作者姓名在内的结果。

固定的json：

DECLARE @json NVARCHAR(MAX) = 
'{
  "header": {
    "type": "esummary",
    "version": "0.3"
  },
  "result": {
    "17784783": {
      "uid": "17784783",
      "pubdate": "2007 Aug",
      "epubdate": "2007 Jul 20",
      "source": "PLoS Comput Biol",
      "sortpubdate": "2007/08/01 00:00",
      "authors": [
        {
          "name": "Yu Y",
          "authtype": "Author",
          "clusterid": ""
        },
        {
          "name": "Wang G",
          "authtype": "Author",
          "clusterid": ""
        },
        {
          "name": "Simha R",
          "authtype": "Author",
          "clusterid": ""
        }
      ]
    },
    "19505939": {
      "uid": "19505939",
      "pubdate": "2009 Aug 1",
      "epubdate": "2009 Jun 8",
      "source": "Bioinformatics",
      "sortpubdate": "2009/08/01 00:00",
      "authors": [
        {
          "name": "Zang C",
          "authtype": "Author",
          "clusterid": ""
        }
      ]
    },
    "30166592": {
      "uid": "30166592",
      "pubdate": "2019 Jan",
      "epubdate": "2018 Aug 30",
      "source": "Oncogene",
      "sortpubdate": "2019/01/01 00:00",
      "authors": [
        {
          "name": "Sun J",
          "authtype": "Author",
          "clusterid": ""
        },
        {
          "name": "Cai X",
          "authtype": "Author",
          "clusterid": ""
        }
      ]
    },
    "uids": [
      "17784783",
      "19505939",
      "30166592"
    ]
  }
}';

使用通用表表达式从json中提取值：

WITH CTE AS
(
    SELECT  [uid], 
            [sortpubdate], 
            [epubdate], 
            [name]
    FROM OPENJSON(@json, N'$.result') AS items
    CROSS APPLY
    -- parse each object in the array
    OPENJSON(items.[value])
    WITH(
        [uid] nvarchar(max) N'$.uid' ,
        [sortpubdate] nvarchar(max) N'$.sortpubdate',
        [epubdate] nvarchar(max) N'$.epubdate',
        -- Note the AS JSON on the next row - will not work without it!
        [authors] nvarchar(max) N'$.authors'  AS JSON 
    ) As content
    CROSS APPLY 
    OPENJSON([authors])
    WITH ([name] nvarchar(max) N'$.name') 
    As authorsNames
    WHERE items.[key] <> 'uids' -- Get only the relevant content
)

并使用stuff和for xml查询cte：

SELECT  DISTINCT [uid], 
        [sortpubdate], 
        [epubdate], 
        STUFF((
            SELECT ',' + [name] 
            FROM CTE As t1
            WHERE t1.[uid] = t0.[uid]
            FOR XML PATH('')
        ), 1, 1, '') As authors
FROM CTE As t0

结果：

uid         sortpubdate         epubdate        authors
17784783    2007/08/01 00:00    2007 Jul 20     Yu Y,Wang G,Simha R
19505939    2009/08/01 00:00    2009 Jun 8      Zang C
30166592    2019/01/01 00:00    2018 Aug 30     Sun J,Cai X

SQL Server 2016存储过程中的串联OPENJSON

1 个答案: