在运行subscriber.py
的RabbitMQ Python客户端上:
import pika, time
credentials = pika.PlainCredentials('user', 'pass')
parameters = pika.ConnectionParameters(host='localhost', port=6672, credentials=credentials)
connection = pika.BlockingConnection(parameters)
channel = connection.channel()
channel.basic_qos(prefetch_count=1)
channel.queue_declare(queue='my_queue')
def callback(ch, method, properties, body):
ch.basic_ack(delivery_tag=method.delivery_tag)
time.sleep(600)
print ('process completed')
channel.basic_consume(queue='my_queue', on_message_callback=callback)
channel.start_consuming()
callback
函数完成后,连接断开。
看来它总是在第60秒发生。看来channel.basic_consume()
方法不想等待主线程完成回调函数。有没有办法确保60秒后连接不会断开?
答案 0 :(得分:0)
您的time.sleep
呼叫阻止了Pika的I / O循环,从而阻止了心跳的处理。 不要阻止I / O循环!
相反,您应该在单独的线程中进行长时间的工作,并从该线程中正确确认消息。幸运的是,我这里有an example:link
注意: RabbitMQ团队监视rabbitmq-users
mailing list,并且有时仅在StackOverflow上回答问题。
答案 1 :(得分:0)
我认为“heartbeat”参数解决了这个问题。只需以秒为单位设置时间:
import pika, time
credentials = pika.PlainCredentials('user', 'pass')
parameters = pika.ConnectionParameters(host='localhost', port=6672, credentials=credentials, heartbeat=36000)
connection = pika.BlockingConnection(parameters)
channel = connection.channel()
channel.basic_qos(prefetch_count=1)
channel.queue_declare(queue='my_queue')
def callback(ch, method, properties, body):
ch.basic_ack(delivery_tag=method.delivery_tag)
time.sleep(600)
print ('process completed')
channel.basic_consume(queue='my_queue', on_message_callback=callback)
channel.start_consuming()