Question

我在MS SQL DB中有一个表，其中包含任何公司的交易，有两列

sub_cat_code
total_amount

total_amount有时包含正值，有时包含负值。正值表示销售，负值表示退货。

现在，我需要使用以下查询找到销售百分比和回报百分比，在返回百分比列中，每个值都相同。任何帮助将是可观的。

Select prod_subcat_code , 
(sum(total_amt)*100 /(select sum(total_amt) from transection)) as 
Sale_pers,
((select sum(total_amt) from transection where total_amt<0)*100/(select 
 sum(total_amt) from transection)) as return_sale
 from transection
 group by prod_subcat_code
 order by Sale_pers desc

Answer 1

使用CTE返回表的总销售额和总回报：

with cte as (
  select 
    sum(case when total_amount > 0 then total_amount else 0 end) total_sales,
    sum(case when total_amount < 0 then total_amount else 0 end) total_returns
  from transection
)
select prod_subcat_code , 
  100.0 * sum(case when total_amount > 0 then total_amount else 0 end) / (select total_sales from cte) as sale_perc,
  100.0 * sum(case when total_amount < 0 then total_amount else 0 end) / (select total_returns from cte) as return_perc
from transection
group by prod_subcat_code

请参见demo。

Answer 2

如果我理解正确，您只想划分两个聚合值：

Select prod_subcat_code,
       sum(total_amt) as net_sales,
       sum(case when total_amt > 0 then total_amt else 0 end) as sales,
       sum(case when total_amt < 0 then total_amt else 0 end) as returns,
       (sum(case when total_amt > 0 then total_amt else 0 end) /
        nullif(sum(total_amt), 0)
       ) as sales_ratio,
       (sum(case when total_amt < 0 then total_amt else 0 end) /
        nullif(sum(total_amt), 0)
       ) as return_ratio
from transection
group by prod_subcat_code;

Answer 3

您可能希望将查询更改为此，以获得所需结果：

Select  prod_subcat_code, 
        sum(case when total_amt > 0 then total_amt else 0 end) as sales,

        (sum(case when total_amt > 0 then total_amt else 0 end) /
        (sum(total_amt)) ) * 100 as sales_Percent,

        sum(case when total_amt < 0 then total_amt else 0 end) as [returns],

        (sum(case when total_amt < 0 then total_amt else 0 end) /
        (sum(total_amt)) ) * 100 as Return_Percent
 from transection
 group by prod_subcat_code
 order by sales_Percent desc

Answer 4

希望它会对您有所帮助，

browser = webdriver.Chrome()
browser.get("http:/link") 
frame_id = 'frame'
wait = WebDriverWait(browser, 10)
wait.until(EC.frame_to_be_available_and_switch_to_it((By.ID, frame_id)))

查找销售百分比和回报百分比

4 个答案: