Question

我有两个相关的模型（Sim和Payment-一个Sim可以有很多Payment）。在搜索Sim（通过ID）时，我希望其详细信息以表格形式（我可以）填充。但是使用相同的表格，我也要保存付款模型的详细信息，同时也要更新Sim模型。

我只能使用id填充Sim表单，但不会填充AddPaymentForm。

def updatePayment(request, id):
    sim  = get_object_or_404(Sim, pk=id)
    payment = AddPaymentForm()
    sim_form = UpdatePayment(request.POST, instance=sim)
    if request.method == "POST":
        # sim_form = UpdatePayment(request.POST, instance=payment)
        payment_form = AddPaymentForm()
        try:
            if payment_form.is_valid():
                payment_form.save()
                sim_form.save()
                messages.success(request, ("Payment has been updated"))
            else:
                messages.warning(request, ("Data in fields is incorrect, please try again"))
        except Exception as e:
            messages.warning(request, ("Error: {}".format(e)))
    else:
        form = UpdatePayment(instance=sim)
        payment = AddPaymentForm()
    context = {'payment': payment, 'form': form,}
    return render(request, 'payment/updatePayment.html', context)

Answer 1

在第7行的代码中，payment_form = AddPaymentForm（）是一个空表格，尚未收到任何数据。应该是

payment_form = AddPaymentForm(request.POST)

确保实例从POST操作接收信息。

        payment_form  = AddPaymentForm(request.POST)
        payment_form = payment_form.save(commit=False) ----> (1)
        try:
            if payment_form.is_valid():
                // Add some logic that links your payment form with SIM form, 
                //for example, like, payment_form(sim=sim_form.id) -------> (2)
                payment_form.save()            
                sim_form.save()
                messages.success(request, ("Payment has been updated"))
            else:
                messages.warning(request, ("Data in fields is incorrect, please try again"))
        except Exception as e:
            messages.warning(request, ("Error: {}".format(e)))

您需要对表单实例进行错误保存，然后才能对表单执行.is_valid（）。
错误地保存表格可让您操纵表格的某些部分，从而使您的Payment_form与新的SIM卡相关联。

Answer 2

您需要使用基于类的视图！

处理多种表单时有两个显着变化。

这是在一个Django视图中使用多种表单的快速示例。

from django.contrib import messages
from django.views.generic import TemplateView

from .forms import AddPostForm, AddCommentForm
from .models import Comment

    class AddCommentView(TemplateView):

        post_form_class = AddPostForm
        comment_form_class = AddCommentForm
        template_name = 'blog/post.html'

        def post(self, request):
            post_data = request.POST or None
            post_form = self.post_form_class(post_data, prefix='post')
            comment_form = self.comment_form_class(post_data, prefix='comment')

            context = self.get_context_data(post_form=post_form,
                                            comment_form=comment_form)

            if post_form.is_valid():
                self.form_save(post_form)
            if comment_form.is_valid():
                self.form_save(comment_form)

            return self.render_to_response(context)     

        def form_save(self, form):
            obj = form.save()
            messages.success(self.request, "{} saved successfully".format(obj))
            return obj

        def get(self, request, *args, **kwargs):
            return self.post(request, *args, **kwargs)

在此示例中，我在线找到了，我们使用TEMPLATE VIEW。基于类的视图是解决此问题的方法。这是有关如何在Django上使用基于类的视图的最新文档的链接。祝您阅读愉快，最重要的是要有耐心。 https://docs.djangoproject.com/en/2.2/topics/class-based-views/

希望这可以帮助您指导正确的方向。期待听到它的进展。

无法在视图中显示两种形式-Django

2 个答案: