Question

我有两个对象数组：

对象1：

    [  
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Screenprint Textile"
   }
]

对象2： [
   {
      “ sku”：“ 30772”，       “ qty”：“ 1”    }，    {
      “ position”：“ Position Arm Left”，       “ tech”：“刺绣”    }，    {
      “ position”：“ Position Chest”，       “ tech”：“丝网印刷纺织品”    } ]

对象2：

[  
   {  
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   }
]

我需要比较对象参数，即position和tech，并需要获得最终的数组，其中该位置和对象如下所示

最终输出：

[  

   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Embroidery"
   }
]

Answer 1

如果使用lodash，则可以使用intersectionWith方法，因为很直观地希望基于两个键进行交点。

const object1 = [
  {
    id: "30772",
    posimage: "/b/l/blue-shirt_1_1.jpg",
    position: "Position Chest",
    tech: "Embroidery"
  },
  {
    id: "30772",
    posimage: "/b/l/blue-shirt_1_1.jpg",
    position: "Position Chest",
    tech: "Screenprint Textile"
  },
  {
    id: "30772",
    posimage: "/b/l/blue-shirt_1_1.jpg",
    position: "Position Arm Left",
    tech: "Embroidery"
  },
  {
    id: "30772",
    posimage: "/b/l/blue-shirt_1_1.jpg",
    position: "Position Arm Left",
    tech: "Screenprint Textile"
  }
];

const object2 = [
  {
    position: "Position Arm Left",
    tech: "Embroidery"
  },
  {
    position: "Position Chest",
    tech: "Screenprint Textile"
  }
];

const result = _.intersectionWith(
  object1,
  object2,
  (o1, o2) => o1.position === o2.position && o1.tech === o2.tech
);

console.log(result);

<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.15/lodash.min.js"></script>

Answer 2

尝试一下，我想这将帮助您获得想要的答案。

const object1 = [  
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Screenprint Textile"
   }
];

const object2 = [  
   {  
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   }
];

const findObject = object1.filter(obj1 => {
  const mathObject = object2.find(obj2 => {
    return obj2.tech === obj1.tech && obj2.position === obj1.position;
  });
  return mathObject;
});

console.log(findObject);

Answer 3

尝试一下：

代码很不言自明。

编辑： 代码现在更加高效，我们确定了两个数组的长度，并使用更少的对象数运行了循环。

var obj1 =   [  
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "id":"30772",
      "posimage":"/b/l/blue-shirt_1_1.jpg",
      "position":"Position Arm Left",
      "tech":"Screenprint Textile"
   }
]

var obj2 = [  
   {  
      "position":"Position Arm Left",
      "tech":"Embroidery"
   },
   {  
      "position":"Position Chest",
      "tech":"Screenprint Textile"
   }
]

const doer = (ob1, ob2) => {
  
  let final = [];
  ob1.map((one) => {
    // let tobepushed = one.hasOwnPropery('id') ? one : two;
    ob2.map(two => {
      if(two.hasOwnProperty('position') && 
          two.hasOwnProperty('tech') && 
          two['position'] === one['position'] && 
          two['tech'] === one['tech']
        ) {
        final.push('id' in one ? one : two);
      }
    })
  })

  return final;
}

let l1 = obj1.length;
let l2 = obj2.length

if(l1 < l2) {
  console.log(doer(obj2, obj1))
} else if (l2 < l1) {
  console.log(doer(obj1, obj2))
}

// console.log(doer(obj2, obj1))

如何使用js比较数组并创建最终数组？

3 个答案: