我有两个桌子
TBL_PRODUCT_TONNAGE
| Product | Jan | Feb | Mar |
+---------------------+------------------+----------+--------+
| E5000 | 91234 | 110000 | 10001 |
| E6000 | 81234 | 120000 | 10002 |
| E7000 | 71234 | 130000 | 10003 |
TBL_PRODUCT_CALORIE
| Product | Jan | Feb | Mar |
+---------------------+------------------+----------+--------+
| E5000 | 5010 | 5020 | 5030 |
| E6000 | 6010 | 6020 | 6030 |
| E7000 | 7010 | 7020 | 7040 |
是否可以将值合并为以下内容 TBL_PRODUCT_COMBINE
| Product | Jan | Feb | Mar |
+---------------------+------------------+----------+--------+
| E5000 | 91234 | 110000 | 1001 |
| E5000_cal | 5010 | 5020 | 5030 |
| E6000 | 81234 | 120000 | 1002 |
| E6000_cal | 6010 | 6020 | 6030 |
| E7000 | 71234 | 130000 | 1003 |
| E7000_cal | 7010 | 7020 | 7030 |
请咨询
答案 0 :(得分:2)
使用union all
:
select product, jan, feb, mar
from tbl_product_tonnage
union all
select product + '_cal', jan, feb, mar
from tbl_product_calories
您的表吞吐量结构是否可以满足您的报告需求?因为它们没有被标准化,但这确实是一个与所要求的问题不同的问题。
这与union
形成对比, ["xxxxx1","xxxxx2","xxxxx3","xxxxx4"]
的作用相同,只是它消除了重复的记录。结果与您的情况相同,但是如果不需要重复数据删除算法,则效率更高。
答案 1 :(得分:0)
select Product, Jan, Feb, Mar
from TBL_PRODUCT_TONNAGE
union
select Product + '_cal', Jan, Feb, Mar
from TBL_PRODUCT_CALORIE
order by Product