Question

我进行了很多搜索，但是找不到如何将套接字绑定到本地主机地址192.168.1.6。

我尝试过

host = "192.168.1.6"
port = 1337
s.bind((host,port))

但是它给出了错误

socket.gaierror: [Errno 11001] getaddrinfo failed

这是我的完整代码：

编辑：- 服务器

import socket

def function(c):
    c.send('HTTP/1.0 200 OK\n'.encode())
    c.send('Content-Type: text/html\n'.encode())
    c.send("""<html> 
              <body>
              <h1> Hello World </h1> this is my server! 
              </body> 
              </html>""".encode())


with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
    s.connect(("122.168.223.131", 80))
    host = s.getsockname()[0]
    print(host)
port = 1337
s = socket.socket()
s.bind((host, port))
s.listen(1)
c, (client_host, client_port) = s.accept()
c.recv(1000)
print('Got connection from', client_host, client_port)
function(c)

客户端：-

from socket import *

host = gethostbyaddr('192.168.1.6')
print()
host_name = host[0]
port = 1337
print(host)
print(host_name)
s = socket(AF_INET, SOCK_STREAM)
s.connect((host_name, port))

第3行“ 192.168.1.6”中的地址是我通过在服务器程序中打印主机得到的地址

Answer 1

我认为您应该这样做：

import socket
host = "...."
port = ...
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
    s.connect((host,port))

Answer 2

“ getaddrinfo失败”错误可能意味着IP地址可能不是您在本地网络上的计算机的地址。试试这个

with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
    s.connect(("8.8.8.8", 80))
    host = s.getsockname()[0]
port = 1337

s = socket.socket()
s.bind((host, port))

如何将套接字绑定到本地地址？

2 个答案: