Question

我需要找到每个项目的MTD（本月至今）和YTD（本年迄今）的销售价值。而且，我可以筛选出需要查找销售报告的全部数据。根据该日期，应该可以找到MTD和YTD的销售额。它应该按条形码对项目进行分组。示例：如果输入以下内容，则在过滤器中：8月21日，我应该找到当天的销售额和MTD，YTD。

当前日期可以正常工作，但是如果我除当前日期以外的任何其他日期都存在，那么MTD和YTD会有差异

SELECT Barcode,
       SUM(CASE WHEN DATE = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), -1) THEN sales_amount ELSE 0 END) AS day_1,
       SUM(CASE
                WHEN MONTH(date) = (MONTH(GETDATE() - 1))
                 AND YEAR(date) = YEAR(GETDATE() - 1) THENsales_amount
                ELSE 0
           END) AS month_t,
       SUM(CASE
                WHEN MONTH(date) = (MONTH(GETDATE() - 1))
                 AND YEAR(date) = YEAR(GETDATE() - 1) - 1 THEN GL_TOTALTTC
                ELSE 0
           END) AS lastyear_tm,
FROM sale
WHERE type = 'FFO'
  AND store = 'AE001A'
  AND (DATE = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), -1)
    OR ((MONTH(date) = (MONTH(GETDATE() - 1))
     AND YEAR(date) = YEAR(GETDATE() - 1))
     OR (MONTH(date) = (MONTH(GETDATE() - 1))
     AND YEAR(date) = YEAR(GETDATE() - 1) - 1)))
GROUP BY barcode;

Answer 1

您可以使用条件聚合：

select bar_code,
       sum(case when date >= dateadd(day, -1, convert(date, getdate()) then sales_amount end) as yesterday,
       sum(case when month(date) = month(getdate()) and year(date) = year(getdate()) then sales_amount end) as mtd,
       sum(case when year(date) = year(getdate()) then sales_amount end) as ytd
from sale
where type = 'FFO' and store = 'AE001A' 
group by barcode;

我需要计算每个商品的日间销售，MTD和年初至今的销售情况

1 个答案: