Question

我正在尝试使用relativedelta查找两个日期之间的月份差异。我可以找到年和天的差异，但是当我筛选月份时，我得到0。有什么建议吗？

from dateutil import relativedelta as rd
import datetime as date 

dateformat = '%Y/%m/%d'
startDate  = date.strptime('2017/07/01',dateformat).date()
endDate = date.strptime('2019/10/29',dateformat).date()

date_diff = rd.relativedelta(endDate,startDate)

print(date_diff.days)

Answer 1

这是解决方案：

from datetime import datetime

def diff_month(d1, d2):
    return (d1.year - d2.year) * 12 + d1.month - d2.month

assert diff_month(datetime(2010,10,1), datetime(2010,9,1)) == 1
assert diff_month(datetime(2010,10,1), datetime(2009,10,1)) == 12

Answer 2

end-start将产生timedelta对象，其天数属性将达到所需的天差

>>> from datetime import date
>>> start = date(2017,7,1)
>>> end = date(2017,11,11)
>>> (end-start).days
133

Answer 3

relativedelta将差异显示为年，月和日。如果这正是您要查找的内容，则不会显示 netmonth 。如果两个日期恰好在不同年份的同一个月，则months属性将为零。

如果要显示总月份，则可以编写一个小函数，通过增加年值来实现。

from datetime import datetime
from dateutil.relativedelta import relativedelta

def month_delta(start_date, end_date):
    delta = relativedelta(end_date, start_date)
    # >>> relativedelta(years=+2, months=+3, days=+28)
    return 12 * delta.years + delta.months

d1 = datetime(2017, 7, 1)
d2 = datetime(2019, 10, 29)
total_months = month_delta(d1, d2)
print(total_months)
# >>> 27

Python：以月为单位计算日期之间的差异

3 个答案: