Question

我想将2个数组合并为新键上的多个数组，并检查相同的键。这是在图像原始数组上，其中suborderid键是确定它们的键

数组1：（$pso）

Array
(
    [0] => Array
        (
            [suborderid] => 127
            [orderid] => 120
        )

    [1] => Array
        (
            [suborderid] => 128
            [orderid] => 120
        )

    [2] => Array
        (
            [suborderid] => 129
            [orderid] => 120
        )

)

数组2：（$items）

Array
(
    [0] => Array
        (
            [suborderid] => 127
            [title] => Kue Nastar
        )

    [1] => Array
        (
            [suborderid] => 128
            [title] => Kue Lapis
        )

    [2] => Array
        (
            [suborderid] => 128
            [title] => Kue Bakar
        )

)

这是我想要的结果

Array
(
    [0] => Array
        (
            [suborderid] => 127
            [orderid] => 120
            [0] => Array
                (
                    [suborderid] => 127
                    [title] => Kue Nastar
                )

        )

    [1] => Array
        (
            [suborderid] => 128
            [orderid] => 120
            [0] => Array
                (
                    [suborderid] => 128
                    [title] => Kue Lapis
                )

            [1] => Array
                (
                    [suborderid] => 128
                    [title] => Kue Bakar
                )

        )

    [2] => Array
        (
            [suborderid] => 129
            [orderid] => 120
        )

)

这是我到目前为止尝试过的：

foreach ($pso as $key => $i){
   foreach ($items as $row => $l){
        $pso[$key]['items'] = $items;   
   }
}

Answer 1

$newPso = [];

foreach ($pso as $val) {
    $newPso[$val["suborderid"]] = $val;
}

foreach ($items as $item) {
    $newPso[$item["suborderid"]][] = $item;
}

$pso = array_values($newPso);

print_r($pso);

首先，我创建一个新数组，其值为$pso数组及其子顺序键的键。

然后，我仅迭代$items数组并添加值。 array_values是为了摆脱新密钥。

演示：https://3v4l.org/QIgjW

Answer 2

尝试一下

$newArr=$pso;
foreach ($pso as $key => $i){
   foreach ($items as $row => $l){
        if($i['suborderid']==$l['suborderid']){ 
        $newArr[$key]['items']=$l;
        }
   }
}

通过检查相同的键在新键上创建多个数组，

2 个答案: