Question

我正在尝试使用javascript从年，月，日之外的数组中获取文本。我不知道该怎么做。

var arr = [
  "power-still-rate-19.08.22", 
  "main-still-rate-19.08.22", 
  "oil-power-rate-19.08.22", 
  "oil-mill-rate-19.7.2"
];
var result;

for (var i = 0; i < arr.length; i++) {
  result = arr[i].remove('?????????');
}
console.log(result);

//result should be like = power-still-rate,main-still-rate,oil-power-rate ;

Answer 1

分割，切片和合并

var arr = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
var result = arr.map(item => item.split("-").slice(0,-1).join("-"))
console.log(result);

拆分，弹出并加入

var arr = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
var result = arr.map(item => { let res = item.split("-"); res.pop(); return res.join("-") })
console.log(result);

没有地图：

var arr = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
var result = arr.join("").split(/-\d{1,}\.\d{1,}\.\d{1,}/);
result.pop(); // last empty item, not needed if you do not want an array just join with comma
console.log(result);

Answer 2

使用正则表达式从字符串开头匹配非数字字符，后跟-和一个数字：

const input = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
const output = input.map(str => str.match(/\D+(?=-\d)/)[0]);
console.log(output);

Answer 3

使用split on -，将最后一个元素（即日期和joining on -）相切

var arr=["power-still-rate-19.08.22","main-still-rate-19.08.22","oil-power-rate-19.08.22"];
    arr.forEach(function(e,i){
    arr[i]=e.split('-').splice(0,3).join('-')
    })
    console.log(arr)

Answer 4

您可以使用String#replace方法来使用RegExp从字符串中删除某些模式。

const input = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
const res = input.map(str => str.replace(/-\d{1,2}\.\d{1,2}\.\d{1,2}$/, ''));
console.log(res);

Answer 5

您可以使用slice函数删除后退字符串，并使用join函数将它们加入。

var arr = ["power-still-rate-19.08.22", "main-still-rate-19.08.22", "oil-power-rate-19.08.22","oil-mill-rate-19.7.2"];
var result = arr.map(str => str.slice(0, str.lastIndexOf('-'))).join(',');
console.log(result);

如何使用JavaScript从字符串中获取特定文本

5 个答案: