Question

此post之后，我尝试将代码从Swift 2.0更新到Swift 5.0，以检查哪些表情符号具有可用的肤色以及是否已经存在其他变体。我详细的更新代码：

extension String {
var emojiSkinToneModifiers: [String] {
    return [ "?", "?", "?", "?", "?" ]
}

var emojiVisibleLength: Int {
    var count = 0
    enumerateSubstrings(in: startIndex..<endIndex, options: .byComposedCharacterSequences) { (_, _, _, _) in
        count = count + 1
    }
    return count
}

var emojiUnmodified: String {
    if self.count == 0 {
        return ""
    }
    let range = String(self[..<self.index(self.startIndex, offsetBy: 1)])
    return range
}

var canHaveSkinToneModifier: Bool {
    if self.count == 0 {
        return false
    }
    let modified = self.emojiUnmodified + self.emojiSkinToneModifiers[0]
    return modified.emojiVisibleLength == 1
}
}

并与数组一起使用：

let emojis = [ "?", "??", "?" ]
for emoji in emojis {
   if emoji.canHaveSkinToneModifier {
        let unmodified = emoji.emojiUnmodified
        print(emoji)
        for modifier in emoji.emojiSkinToneModifiers {
            print(unmodified + modifier)
        }
    } else {
      print(emoji)
    }
 }

输出： ??????????? 为没有表情符号或没有表情符号的表情符号分配变体：：?

我认为enumerateSubstringsInRange是不正确的，并且self.characters.count现在变得self.count容易和正确地计算了一个表情符号（由组成）与before Swift 4相比，但在这种情况下可能没有用。我没看错吗？谢谢

Answer 1

“ hack”是比较正确表情符号（如“?”）和想要成为表情符号（如“??”）的视觉表示）。

我已经在这里和那里修改了您的代码以使其正常工作：

extension String {
    static let emojiSkinToneModifiers: [String] =  ["?", "?", "?", "?", "?"]

    var emojiVisibleLength: Int {
        var count = 0
        let nsstr = self as NSString
        let range = NSRange(location: 0, length: nsstr.length)
        nsstr.enumerateSubstrings(in: range,
                            options: .byComposedCharacterSequences)
        { (_, _, _, _) in

            count = count + 1
        }
        return count
    }

    var emojiUnmodified: String {
        if isEmpty {
            return self
        }
        let string = String(self.unicodeScalars.first!)
        return string
    }

    private static let emojiReferenceSize: CGSize = {
        let size = CGSize(width : CGFloat.greatestFiniteMagnitude,
                          height: CGFloat.greatestFiniteMagnitude)
        let rect = ("?" as NSString).boundingRect(with: size,
                                                     options: .usesLineFragmentOrigin,
                                                     context: nil)
        return rect.size
    }()

    var canHaveSkinToneModifier: Bool {
        if isEmpty {
            return false
        }

        let modified = self.emojiUnmodified + String.emojiSkinToneModifiers[0]

        let size = (modified as NSString)
            .boundingRect(with: CGSize(width : CGFloat.greatestFiniteMagnitude,
                                       height: .greatestFiniteMagnitude),
                          options: .usesLineFragmentOrigin,
                          context: nil).size

        return size == String.emojiReferenceSize
    }
}

让我们尝试一下：

let emojis = [ "?", "??", "?" ]
for emoji in emojis {
    if emoji.canHaveSkinToneModifier {
        let unmodified = emoji.emojiUnmodified
        print(unmodified)
        for modifier in String.emojiSkinToneModifiers {
            print(unmodified + modifier)
        }
    } else {
        print(emoji)
    }
    print("\n")
}

瞧！

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表情符号肤色检测

1 个答案: