Question

所以我在不同的旧帖子中使用下面的代码，但是有一部分出现问题，HttpGet request = new HttpGet(url);的行不起作用。在网址中我添加了类似www.stackoverflow.com的内容，但是这一部分不会让代码编译。我基本上试图从HTML网站上写文字。完整的代码：

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    HttpClient client = new DefaultHttpClient();
    HttpGet request = new HttpGet(www.stackoverflow.com);
    HttpResponse response = client.execute(request);

    String html = "Toronto-GTA";
    InputStream in = response.getEntity().getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    StringBuilder str = new StringBuilder();
    String line = null;
    while((line = reader.readLine()) != null)
    {
        str.append(line);
    }
    in.close();
    html = str.toString();
}

Answer 1

HTTPGet需要URL或字符串，因此请尝试将您的请求行更改为：

HttpGet request = new HttpGet("http://www.stackoverflow.com/");

Answer 2

使用以下形式的字符串：

[scheme:][//authority][path][?query][#fragment]

即。 "http://www.stackoverflow.com"

Answer 3

试试这个：HttpGet request = new HttpGet("www.stackoverflow.com");

Answer 4

使用try和catch语句添加上面给出的答案，以捕获异常。

try{
HttpClient client = new DefaultHttpClient();
    HttpGet request = new HttpGet("www.stackoverflow.com");
    HttpResponse response = client.execute(request);
    InputStream in = response.getEntity().getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    StringBuilder str = new StringBuilder();
    String line, html = null;
    while((line = reader.readLine()) != null)
    {
        str.append(line);
    }
    in.close();
    html = str.toString();
}
catch(Exception e){
//Do something here like printing the stacktrace
}

HttpGet无法识别网址

4 个答案: