Question

假设我有两个对象列表

List1 = [{"name" : "Mac", "age":24, "id" : 1},
         {"name" : "Mona","age":22, "id" : 2}]

和

List2 = [{"type" : "human","country":"AUS"}]

如何将列表2中的所有元素附加到列表1中的所有元素这样最终的list1看起来就像

[{"name" : "Mac", "age":24, "id" : 1, "type" : "human","country":"AUS"},{"name" : "Mona", "age":22, "id" : 2, "type" : "human","country":"AUS"}]

当前正在遍历并在列表上进行更新，该列表正在运行，但是我想知道是否有更简便，更好的方法来完成此操作

for person in List1:    
  person.update(List2) 
print List1

Answer 1

List1 = [{"name" : "Mac", "age":24, "id" : 1},
     {"name" : "Mona","age":22, "id" : 2}]

List2 = [{"type" : "human","country":"AUS"}]

List1 = List1 + List2

这将起作用，我已经在Python 2.7中进行了检查。希望这个答案有帮助。

Answer 2

您也可以尝试以下代码-

List1 = [{"name" : "Mac", "age":24, "id" : 1},
     {"name" : "Mona","age":22, "id" : 2}]

List2 = [{"type" : "human","country":"AUS"}]

finalList = [dict(l.items() + List2[0].items()) for l in List1]

print finalList

合并两个将所有参数从list2插入list1的列表

2 个答案: