Question

基本上，当我们输入

之类的列表时

[['Bilbo', 'Baggins'], ['Gollum'], ['Tom', 'Bombadil'], ['Aragorn']]

在函数中，它应该在单独的行中打印出每个列表中的元素，并在它们之间留一个空格。当每个列表中的元素数不相等时，我不知道该怎么办。

我也不允许使用任何for循环

这是我的代码：

def print_names2(people):
"""Print a list of people's names, which each person's name
   is itself a list of names (first name, second name etc)
"""
    i = 0
    while i < len(people):
        names = list(people[i])
        j = 0
        while j < len(names):
            i += 1
            name = names[j]
            print(name, end=" ")
            j += 1
print_names2([['Bilbo', 'Baggins'], ['Gollum'], ['Tom', 'Bombadil'], 
['Aragorn']])

预期结果：

Bilbo Baggins 
Gollum 
Tom Bombadil 
Aragorn

实际结果：

Bilbo Baggins Tom Bombadil

我应该对我的代码进行哪些更改？

谢谢。

Answer 1

尝试一种更简单的方法。

router.post(
  "/",
  [
    check("name", "Name is required")
      .not()
      .isEmpty(),
    check("email", "Please include valid email").isEmail(),
    check(
      "password",
      "Please enter password with 5 or more characters"
    ).isLength({ min: 5 })
  ],
  (req, res) => {
    const errors = validationResult(req);
    if (!errors.isEmpty()) {
      return res.status(400).json({ errors: errors.array() });
    }
    res.send("User Route");
  }
);

输出

def print_names(people):
    for i in people:
        print (' '.join(i))

people=[['Bilbo', 'Baggins'], ['Gollum'], ['Tom', 'Bombadil'], ['Aragorn']]
print_names(people)

不使用Bilbo Baggins Gollum Tom Bombadil Aragorn循环。

for

Answer 2

您只需要在初始while循环的末尾打印一个空行。

def print_names2(people):
"""Print a list of people's names, which each person's name
   is itself a list of names (first name, second name etc)
"""
    i = 0
    while i < len(people):
        names = list(people[i])
        j = 0
        while j < len(names):
            i += 1
            name = names[j]
            print(name, end=" ")
            j += 1
        print("")    

print_names2([['Bilbo', 'Baggins'], ['Gollum'], ['Tom', 'Bombadil'], 
['Aragorn']])

打印人名列表，每个人的名字本身就是人名列表

2 个答案: