Question

能否请您分享一些用于Firebase-admin身份验证的Sinon存根示例。面临的挑战是初始化Firebase管理应用程序以获取更多存根。

我尝试了下一个代码

  const admin = require('firebase-admin');
  sinon.stub(admin, 'initializeApp');
  var noUserError = new Error('error');
  noUserError.code = 'auth/user-not-found';
  sinon.stub(admin, 'auth').returns({
    getUserByEmail: sinon.fake.rejects(noUserError)
  });
  var err = await admin.auth().getUserByEmail(email);
  console.error(err);

但返回

  Error (FirebaseAppError) {
    codePrefix: 'app',
    errorInfo: {
      code: 'app/no-app',
      message: 'The default Firebase app does not exist. Make sure you call initializeApp() before using any of the Firebase services.',
    },
    message: 'The default Firebase app does not exist. Make sure you call initializeApp() before using any of the Firebase services.',
  }

预期结果是异常错误，代码='auth / user-not-found'

Answer 1

由于admin.auth是一个getter，您不能将其存为一个函数，而只能将其作为存根（stub）对象返回一个函数。您需要使用Sinon API中的stub.get(getterFn)。

sinon.stub(admin, 'auth').get(() => () => ({
  getUserByEmail: sinon.fake.rejects(noUserError)
}));

Answer 2

使用firebase-mock帮助了。

https://github.com/soumak77/firebase-mock

  const firebasemock = require('firebase-mock');
  const mockauth = new firebasemock.MockAuthentication();
  const mockdatabase = new firebasemock.MockFirebase();
  const mocksdk = new firebasemock.MockFirebaseSdk(
    (path) => {
      return path ? mockdatabase.child(path) : mockdatabase;
    },
    () => {
      return mockauth;
    }
  );
  mocksdk.auth().autoFlush();

  proxyquire('../index', {
    'firebase-admin': mocksdk
  });

如何使用sinon存根require（'firebase-admin'）。auth（）。getUserByEmail（）？

2 个答案: