Question

我有以下代码将工作表导出为.CSV文件。它将使用当前文件名和当前位置创建.CSV格式的新文件。

想要以某种方式修改它，它应该从单元格N15中选择要保存的文件名，并且应该将其保存在预定义的路径中。

Sub ExportAsCSV()

Dim MyFileName As String
Dim CurrentWB As Workbook, TempWB As Workbook

Set CurrentWB = ActiveWorkbook
ActiveWorkbook.ActiveSheet.UsedRange.Copy

Set TempWB = Application.Workbooks.Add(1)
With TempWB.Sheets(1).Range("A1")
.PasteSpecial xlPasteValues
.PasteSpecial xlPasteFormats
 End With        

Dim Change below to "- 4"  to become compatible with .xls files
MyFileName = CurrentWB.Path & "\" & Left(CurrentWB.Name, 
Len(CurrentWB.Name) - 5) & ".csv"

Application.DisplayAlerts = False
TempWB.SaveAs Filename:=MyFileName, FileFormat:=xlCSV, 
CreateBackup:=False, Local:=True
TempWB.Close SaveChanges:=False
Application.DisplayAlerts = True
End Sub

Answer 1

只需更改文件名变量中的值

Sub ExportAsCSV()

    Dim MyFileName As String
    Dim CurrentWB As Workbook, TempWB As Workbook

    Set CurrentWB = ActiveWorkbook
    ActiveWorkbook.ActiveSheet.UsedRange.Copy

    Set TempWB = Application.Workbooks.Add(1)
    With TempWB.Sheets(1).Range("A1")
    .PasteSpecial xlPasteValues
    .PasteSpecial xlPasteFormats
     End With        

    Dim Change below to "- 4"  to become compatible with .xls files
    MyFileName = CurrentWB.Path & "\" & Range("N15").value2

    Application.DisplayAlerts = False
    TempWB.SaveAs Filename:=MyFileName, FileFormat:=xlCSV, 
    CreateBackup:=False, Local:=True
    TempWB.Close SaveChanges:=False
    Application.DisplayAlerts = True
    End Sub

从单元格引用获取文件名和路径

1 个答案: