我有一个弹性查询脚本，该脚本用于使用给定的参数计算地面距离，并且必须在多个查询中使用该距离。是否有避免这种重复的方法，例如，一种用于计算全局变量的方法并在本示例中的所有脚本中使用它，我想计算distance并在其他查询中使用它，而不是每次都不计算。
"query":{
"bool":{
"filter":[
{
"script":{
"script":{
"lang":"painless",
"params":{
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"28060":2569.7,
"minDistance":0
},
"source":"def a=doc['id'].getValue();if (!params.containsKey(a.toString())) {return false;}double distance=params[a.toString()]; return distance <= doc['maxClassDeliveryDistance'].getValue() && distance >= params['minDistance']"
}
}
},
{
"script":{
"script":{
"lang":"painless",
"params":{
"9183":4896.4,
"9238":7487.3,
"9239":7491.2,
"9402":5150.7,
"9618":2069.5,
"9656":4028.6,
"9660":3612.1,
"10049":2823.4,
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"10479":5167.8,
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},
"source":"def a=doc['id'].getValue();if (!params.containsKey(a.toString())) {return false;}double distance=params[a.toString()];return distance <= doc['maxDeliveryRadius'].getValue()"
}
}
}
]
}
}
}
映射：
{
"id":{
"type":"long"
},
"maxClassDeliveryDistance":{
"type":"long"
},
"maxDeliveryRadius":{
"type":"long"
}
}
答案 0 :(得分：2)
您应该改用stored script，以便按ID引用它：
POST _scripts/distance-script
{
"script": {
"lang": "painless",
"source":"def a=doc['id'].getValue();if (!params.containsKey(a.toString())) {return false;}double distance=params[a.toString()];return distance <= doc['maxDeliveryRadius'].getValue()"
}
}
然后您可以在查询中引用上述脚本：
{
"query": {
"bool": {
"filter": [
{
"script": {
"script": {
"lang": "painless",
"params": { ... },
"id": "distance-script"
}
}
},
{
"script": {
"script": {
"lang": "painless",
"params": { ... },
"id": "distance-script"
}
}
}
]
}
}
}
更新
我认为我们可以解决不同的问题。 bool/filter中有两个脚本查询，这意味着AND。另外，两个脚本中的参数相同。因此，您可以将这两个脚本组合在一起，而无需使用一个脚本，就像这样：
POST _scripts/distance-script
{
"script": {
"lang": "painless",
"source":"""
def a = doc.id.value.toString();
if (!params.containsKey(a) {
return false;
}
double distance = params[a];
return distance <= doc.maxClassDeliveryDistance.value && distance >= params['minDistance'] && distance <= doc.maxDeliveryRadius.value;
"""
}
}