Question

“我想将ID和文件数据发送到同一操作uploadFile（int id，httpPostFileBase upFile）吗？”

我试图在提交过程中通过ajax发送患者ID，并使用输入标签中的name属性来文件。

@using (Html.BeginForm("uploadFile", "patientsProfile", FormMethod.Post, new { enctype = "multipart/form-data" }))
    {

        <input type="file" name="upFile" />
        <br />
        <input type="submit" name="submit" value="Upload!" />
    }

var id = url.substring(url.lastIndexOf('/') + 1);

$("form").submit(function (e) {
                $.ajax({
                    type: "POST",
                    url: "@Url.Action("uploadFile","patientsProfile")",
                    data: {
                        Id: id
                    },
                    success: function (res) {
                        alert("id :" + id);
                    }
                })
            })

[HttpPost]
        public ActionResult uploadFile( HttpPostedFileBase upFile , int Id)
        {
            Tests tests = new Tests();

            tests.patients_Id = Id;

            string fileName = upFile.FileName;

            string UniquefileName = Guid.NewGuid() + Path.GetFileName(upFile.FileName);

            string filePath = Server.MapPath("~/Uploaded/");


            string actualPath = Path.Combine(filePath + UniquefileName);
            upFile.SaveAs(actualPath);

            tests.Name = fileName;
            tests.urlName = actualPath;
            db.Tests.Add(tests);
            db.SaveChanges();

            return RedirectToAction("index");
        }

httpPostFileBase upFile 为空，但id正确获取其值

Answer 1

首先，我认为下面的代码会引起问题

var id = url.substring(url.lastIndexOf('/') + 1);

原因

如果在id仅为一个字符时用于获取ID，则它会很好地工作，但是当字符数增加时，它将获得错误的值。网址 www.yourdomain.com/controller/action/1 的示例，它可以正常工作，但 www.yourdomain.com/controller/action / 12 将返回与第一个相同的结果。因此，您可能想在那里做一些数学运算，例如 （stringLength-lastIndexOf /）

我建议您使用ViewBag来获取该ID，因为它是通过GET方法传递的，然后将其作为参数传递给表单，如下所示

@using (Html.BeginForm("uploadFile", "Home", new{Id = ViewBag.Id}, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    <input type="file" name="upFile" id="upFile" />
    <br />
    <input type="submit" name="submit" value="Upload!" />
}

请记住将视图包作为

包含在get请求中

public ActionResult ActionName(int Id)
{
    ViewBag.Id = Id;
    return View();
}

如果您坚持使用JavaScript，然后尝试将文件作为数据包含在此answer

中

Answer 2

您必须将upFile传递到您要发送的数据。

data: {
    Id: id,
    upFile: //the file which you are sending
},

Answer 3

       @using (Html.BeginForm("uploadFile", "Home", new{Id = ViewBag.Id}, 
       FormMethod.Post, new { enctype = "multipart/form-data" }))
       {
       <input type="file" name="upFile" id="upFile" />
       <input type="hidden" name="hdfid" id="hdfid" value ="" />
       <br />
       <input type="submit" name="submit" value="Upload!" />
       }


       var id = url.substring(url.lastIndexOf('/') + 1);

         $("#hdfid").val(id);
            $("form").submit(function (e) {
            $.ajax({
                type: "POST",
                url: "@Url.Action("uploadFile","patientsProfile")",

                success: function (res) {
                    alert("id :" + id);
                }
            })
        })







        public ActionResult uploadFile( formcollection form, HttpPostedFileBase 
        upFile )
        {
            Tests tests = new Tests();
            string id = form["id"];//or provide index
            tests.patients_Id = Id;

            string fileName = upFile.FileName;

            string UniquefileName = Guid.NewGuid() + 
            Path.GetFileName(upFile.FileName);

            string filePath = Server.MapPath("~/Uploaded/");


            string actualPath = Path.Combine(filePath + UniquefileName);
            upFile.SaveAs(actualPath);

            tests.Name = fileName;
            tests.urlName = actualPath;
            db.Tests.Add(tests);
            db.SaveChanges();

            return RedirectToAction("index");
        }

如何将ID和文件发送到同一控制器？

3 个答案: