Azure管道具有Expressions和Conditions,但是我找不到基于条件将两个值之一分配给variable的方法。
有什么办法可以完成这个伪代码吗?
${{ if endsWith( variables['Build.SourceBranchName'], '/master' ) }}:
buildVersion: variables['mavenVersion']
${{ else }}:
buildVersion: variables['Build.SourceBranchName']
答案 0 :(得分:9)
作为@Mike Murray答案的扩展,如果使用变量组,则必须将其他变量定义为名称/值对。在这种情况下,使用条件变量赋值如下:
{{1}}
答案 1 :(得分:6)
我比我想像的要近。这虽然不漂亮,但确实有效。 (具有更多yaml上下文)
variables:
${{ if eq( variables['Build.SourceBranchName'], 'master' ) }}:
buildVersion: ${{ variables['mavenVersion'] }}
${{ if ne( variables['Build.SourceBranchName'], 'master' ) }}:
buildVersion: ${{ variables['Build.SourceBranchName'] }}
buildKey: ${{ format('{0}_{1}', variables['supportReleaseNumber'], variables['buildVersion']) }}
buildNum: $[counter(variables['buildKey'], 1)] # same as $(Rev:r), but more widely usable
name: $(buildKey)_$(buildNum) # build run name
答案 2 :(得分:2)
这应该可以解决问题。...
BuildVersion初始化为$(Build.SourceBranch) 如果是主分支,则将其更改为$(mavenVersion) 否则没有变化。
variables:
mavenVersion: '1.0'
buildVersion: $(Build.SourceBranch)
pool:
vmImage: 'ubuntu-latest'
steps:
- script: echo '##vso[task.setvariable variable=buildVersion]$(mavenVersion)'
displayName: "Set the buildVersion as mavenVersion if the Build.SourceBranch = 'refs/heads/master' "
condition: eq(variables['Build.SourceBranch'], 'refs/heads/master')
- script: echo $(buildVersion)
displayName: 'Printing the variable'
答案 3 :(得分:1)
@Mike Murray,谢谢您!我一直试图解决这个问题。 当从拉取请求触发构建时,SourceBranchName始终为“合并”。您的回答帮助我提出了此解决方案,以获取两种情况下的目标分支名称:手动构建和由pull-requests触发的构建:
${{ if ne( variables['Build.SourceBranchName'], 'merge' ) }}:
environment: ${{ variables['Build.SourceBranchName'] }}
${{ if endsWith( variables['System.PullRequest.TargetBranch'], 'dev' ) }}:
environment: dev
${{ if endsWith( variables['System.PullRequest.TargetBranch'], 'staging' ) }}:
environment: staging
${{ if endsWith( variables['System.PullRequest.TargetBranch'], 'master' ) }}:
environment: prod
不是很漂亮,但是终于可以了。