我正在研究Wes Bos的一个项目,您的任务是向一系列列表项中添加Shift Click功能。
我完成了此操作,然后想通过添加取消选择这些列表项的功能来做进一步的工作(请参阅注释的javascript代码)。
然后我想采用该解决方案并应用DRY原理,这就是事情变得困难的地方。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Hold Shift to Check Multiple Checkboxes</title>
</head>
<body>
<style>
html {
font-family: sans-serif;
background: #ffc600;
}
.inbox {
max-width: 400px;
margin: 50px auto;
background: white;
border-radius: 5px;
box-shadow: 10px 10px 0 rgba(0,0,0,0.1);
}
.item {
display: flex;
align-items: center;
border-bottom: 1px solid #F1F1F1;
}
.item:last-child {
border-bottom: 0;
}
input:checked + p {
background: #F9F9F9;
text-decoration: line-through;
}
input[type="checkbox"] {
margin: 20px;
}
input:hover {
cursor: pointer;
}
p {
margin: 0;
padding: 20px;
transition: background 0.2s;
flex: 1;
font-family:'helvetica neue';
font-size: 20px;
font-weight: 200;
border-left: 1px solid #D1E2FF;
}
</style>
<!--
The following is a common layout you would see in an email client.
When a user clicks a checkbox, holds Shift, and then clicks another checkbox a few rows down, all the checkboxes inbetween those two checkboxes should be checked.
-->
<div class="inbox">
<div class="item">
<input type="checkbox">
<p>This is an inbox layout.</p>
</div>
<div class="item">
<input type="checkbox">
<p>Check one item</p>
</div>
<div class="item">
<input type="checkbox">
<p>Hold down your Shift key</p>
</div>
<div class="item">
<input type="checkbox">
<p>Check a lower item</p>
</div>
<div class="item">
<input type="checkbox">
<p>Everything in between should also be set to checked</p>
</div>
<div class="item">
<input type="checkbox">
<p>Try to do it without any libraries</p>
</div>
<div class="item">
<input type="checkbox">
<p>Just regular JavaScript</p>
</div>
<div class="item">
<input type="checkbox">
<p>Good Luck!</p>
</div>
<div class="item">
<input type="checkbox">
<p>Don't forget to tweet your result!</p>
</div>
</div>
<script>
const input = document.querySelectorAll('.item input[type="checkbox"]');
let lastchecked;
function checkFunction (event) {
let inbetween = false;
if (event.shiftKey && this.checked) {
tickBox(true);
} else if (event.shiftKey && !this.checked) {
tickBox(false);
}
lastChecked = this;
}
function tickBox(boolean) {
input.forEach(box => {
if (box === this || box === lastChecked) {
inbetween = !inbetween;
}
if (inbetween) {
box.checked = boolean;
}
});
}
input.forEach(box => box.addEventListener('click', checkFunction));
// const input = document.querySelectorAll('.item input[type="checkbox"]');
// let lastchecked;
//
// function checkFunction (event) {
// let inbetween = false;
// if (event.shiftKey && this.checked) {
// input.forEach(box => {
// if (box === this || box === lastChecked) {
// inbetween = !inbetween;
// }
// if (inbetween) {
// box.checked = true;
// }
// });
// } else if (event.shiftKey && !this.checked) {
// input.forEach(box => {
// if (box === this || box === lastChecked) {
// inbetween = !inbetween;
// }
// if (inbetween) {
// box.checked = false;
// }
// });
// }
// lastChecked = this;
// }
//
// input.forEach(box => box.addEventListener('click', checkFunction));
</script>
</body>
</html>
我当时希望我要做的只是调用重复代码的函数,但是这次使用布尔参数,但是它表示inbetween变量未定义。在这一点上,我感到困惑。如果我在新函数中定义它,它只会勾选所有内容,并且不会将变量更改回false等。
我希望这是有道理的。我很想知道我将来会出错。
谢谢。
答案 0 :(得分:0)
我建议在tickBox()
内声明checkFunction()
。这是可行的,因为从未在其他地方调用过它。然后,它可以访问checkFunction()
的范围,包括inbetween
变量:
const input = document.querySelectorAll('.item input[type="checkbox"]');
let lastchecked;
function checkFunction (event) {
let inbetween = false;
function tickBox(boolean) {
input.forEach(box => {
if (box === this || box === lastChecked) {
inbetween = !inbetween;
}
if (inbetween) {
box.checked = boolean;
}
});
}
if (event.shiftKey && this.checked) {
tickBox(true);
} else if (event.shiftKey && !this.checked) {
tickBox(false);
}
lastChecked = this;
}
input.forEach(box => box.addEventListener('click', checkFunction));
仅供参考,您可以通过以下方式简化i f/else
:
if (event.shiftKey && this.checked) {
tickBox(true);
} else if (event.shiftKey && !this.checked) {
tickBox(false);
}
对此:
if (event.shiftKey) {
tickBox(this.checked);
}
这意味着您实际上不再需要tickBox()
的单独功能。